如何使用 Python 将文本文件读入列表或数组 [英] How to read a text file into a list or an array with Python

问题描述

我正在尝试将文本文件的行读入 python 中的列表或数组.我只需要能够在创建后单独访问列表或数组中的任何项目.

I am trying to read the lines of a text file into a list or array in python. I just need to be able to individually access any item in the list or array after it is created.

文本文件格式如下:

0,0,200,0,53,1,0,255,...,0.

... 在上面的地方，实际的文本文件有成百上千个项目.

Where the ... is above, there actual text file has hundreds or thousands more items.

我正在使用以下代码尝试将文件读入列表:

I'm using the following code to try to read the file into a list:

text_file = open("filename.dat", "r")
lines = text_file.readlines()
print lines
print len(lines)
text_file.close()

我得到的输出是:

['0,0,200,0,53,1,0,255,...,0.']
1

显然，它是将整个文件读入只有一个项目的列表，而不是单个项目的列表.我做错了什么?

Apparently it is reading the entire file into a list of just one item, rather than a list of individual items. What am I doing wrong?

推荐答案

您必须使用 split()

所以，

lines = text_file.read().split(',')

我没有意识到这会有如此大的吸引力.这是一种更惯用的方法.

I didn't realise there would be so much traction to this. Here's a more idiomatic approach.

import csv
with open('filename.csv', 'r') as fd:
    reader = csv.reader(fd)
    for row in reader:
        # do something

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