Numpy 矩阵到数组 [英] Numpy matrix to array
问题描述
我正在使用 numpy.我有一个包含 1 列和 N 行的矩阵,我想从中获取一个包含 N 个元素的数组.
I am using numpy. I have a matrix with 1 column and N rows and I want to get an array from with N elements.
例如,如果我有 M = matrix([[1], [2], [3], [4]])
,我想得到 A = array([1,2,3,4])
.
For example, if i have M = matrix([[1], [2], [3], [4]])
, I want to get A = array([1,2,3,4])
.
为了实现它,我使用 A = np.array(M.T)[0]
.有谁知道获得相同结果的更优雅的方法?
To achieve it, I use A = np.array(M.T)[0]
. Does anyone know a more elegant way to get the same result?
谢谢!
推荐答案
如果你想要一些更具可读性的东西,你可以这样做:
If you'd like something a bit more readable, you can do this:
A = np.squeeze(np.asarray(M))
等效地,您也可以这样做:A = np.asarray(M).reshape(-1)
,但这不太容易阅读.
Equivalently, you could also do: A = np.asarray(M).reshape(-1)
, but that's a bit less easy to read.
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