获取没有数组名称的 JSONArray? [英] Get JSONArray without array name?
问题描述
我是 JSON 新手，正在尝试本教程:http://p-xr.com/android-tutorial-how-to-parse-read-json-data-into-a-android-listview/#comments
我是 JSON、C 语言、Java 和 Android 的新手，但我正在学习.本教程使用我所说的命名数组，但我将在我的 android 项目中使用的所有 JSON 都将使用没有命名数组的简单表行.我正在使用的 JSON 示例和教程中的地震 json 示例如下.
本教程遍历地震数组并使用以下代码转换为 JAVA hashmap 列表:
JSONArray 地震 = json.getJSONArray("earthquakes");for(int i=0;i<earthquakes.length();i++){HashMap<字符串，字符串>map = new HashMap();JSONObject e = 地震.getJSONObject(i);map.put("id", String.valueOf(i));map.put("name", "地震名称:" + e.getString("eqid"));map.put("magnitude", "Magnitude:" + e.getString("magnitude"));mylist.add(map);} 我的问题是，如果我的 JSON 如下所示，我该如何使用 json.getJSONArray("") ?我可以转换其余的代码，如果我没有 strJsonArrayName，我只需要知道如何使用 getJSONArray("strJsonArrayName") 加载该 JSON.
我的 JSON(未命名数组)
<预><代码>[{"cnt":1,"name":"美国人",PK":7},{"cnt":2,"name":"名人",PK":3},{"cnt":1,"name":"女",PK":2},{"cnt":1,"name":"语言",PK":8},{"cnt":1,"name":"男",PK":1},{"cnt":1,"name":"地区",PK":9}]教程的 JSON(命名数组)
<代码>{地震":[{"eqid":"c0001xgp",幅度":8.8，"lng":142.369,"src":"我们","日期时间":"2011-03-11 04:46:23",深度":24.4，纬度":38.322},{"eqid":"c000905e",幅度":8.6，"lng":93.0632,"src":"我们","日期时间":"2012-04-11 06:38:37",深度":22.9，纬度":2.311},{"eqid":"2007hear",幅度":8.4，"lng":101.3815,"src":"我们","日期时间":"2007-09-12 09:10:26",深度":30，纬度":-4.5172},{"eqid":"c00090da",幅度":8.2，"lng":92.4522,"src":"我们","日期时间":"2012-04-11 08:43:09",深度":16.4，纬度":0.7731},{"eqid":"2007aqbk",幅度":8，"lng":156.9567,"src":"我们","日期时间":"2007-04-01 18:39:56",深度":10，纬度":-8.4528},{"eqid":"2007hec6",幅度":7.8，"lng":100.9638,"src":"我们","日期时间":"2007-09-12 21:49:01",深度":10，纬度":-2.5265},{"eqid":"a00043nx",幅度":7.7，"lng":100.1139,"src":"我们","日期时间":"2010-10-25 12:42:22",深度":20.6，纬度":-3.4841},{"eqid":"2010utc5",幅度":7.7，"lng":97.1315,"src":"我们","日期时间":"2010-04-06 20:15:02",深度":31，纬度":2.3602},{"eqid":"2009mebz",幅度":7.6，"lng":99.9606,"src":"我们","日期时间":"2009-09-30 08:16:09",深度":80，纬度":-0.7889},{"eqid":"2009kdb2",幅度":7.6，"lng":92.9226,"src":"我们","日期时间":"2009-08-10 17:55:39",深度":33.1，纬度":14.0129}]}在本教程中，根据@MДΓΓ БДLL 和@Cody Caughlan 的回答，我能够将 JSONFunctions.getJSONFromURL 重新格式化为 JSONArray 而不是 JSONObject.这是我修改后的工作代码，谢谢！
公共类 JSONfunctions {公共静态 JSONArray getJSONfromURL(String url){输入流是 = null;字符串结果 = "";JSONArray jArray = null;HttpClient httpclient = new DefaultHttpClient();HttpGet httpget = new HttpGet(url);HttpResponse 响应 = httpclient.execute(httpget);HttpEntity entity = response.getEntity();is = entity.getContent();BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);StringBuilder sb = new StringBuilder();字符串行 = null;while ((line = reader.readLine()) != null) {sb.append(line + "\n");}is.close();结果= sb.toString();jArray = new JSONArray(result);返回 jArray;}}您根本不需要调用 json.getJSONArray()，因为您正在使用的 JSON 是 一个数组.所以，不要构造 JSONObject 的实例；使用 JSONArray.这应该足够了:
//...JSONArray json = 新的 JSONArray(result);//...for(int i=0;i<json.length();i++){HashMap<字符串，字符串>map = new HashMap();JSONObject e = json.getJSONObject(i);map.put("id", String.valueOf(i));map.put("name", "地震名称:" + e.getString("eqid"));map.put("magnitude", "Magnitude:" + e.getString("magnitude"));mylist.add(map);} 您不能使用与教程中完全相同的方法，因为您正在处理的 JSON 需要在根处解析为 JSONArray，而不是 JSONObject.
I'm new to JSON and trying this tutorial: http://p-xr.com/android-tutorial-how-to-parse-read-json-data-into-a-android-listview/#comments
I'm new to JSON, C languages, Java and also Android, but am learning. The tutorial uses what I'm calling a named array, but all of the JSON i'm going to be using in my android project will use simple table rows with no named array. Examples of the JSON i'm using and the earthquake json from the tutorial are below.
The tutorial iterates through the earthquake array and converts into a JAVA hashmap list using the following code:
JSONArray earthquakes = json.getJSONArray("earthquakes");
for(int i=0;i<earthquakes.length();i++){
HashMap<String, String> map = new HashMap<String, String>();
JSONObject e = earthquakes.getJSONObject(i);
map.put("id", String.valueOf(i));
map.put("name", "Earthquake name:" + e.getString("eqid"));
map.put("magnitude", "Magnitude: " + e.getString("magnitude"));
mylist.add(map);
}
My question is, how can I use json.getJSONArray("") if my JSON is just simple as below? I can convert the rest of the code, I just need to know how to load that JSON using the getJSONArray("strJsonArrayName") if I don't have a strJsonArrayName.
My JSON (UnNamed Array)
[
{
"cnt":1,
"name":"American",
"pk":7
},
{
"cnt":2,
"name":"Celebrities",
"pk":3
},
{
"cnt":1,
"name":"Female",
"pk":2
},
{
"cnt":1,
"name":"Language",
"pk":8
},
{
"cnt":1,
"name":"Male",
"pk":1
},
{
"cnt":1,
"name":"Region",
"pk":9
}
]
Tutorial's JSON (Named Array)
{
"earthquakes":[
{
"eqid":"c0001xgp",
"magnitude":8.8,
"lng":142.369,
"src":"us",
"datetime":"2011-03-11 04:46:23",
"depth":24.4,
"lat":38.322
},
{
"eqid":"c000905e",
"magnitude":8.6,
"lng":93.0632,
"src":"us",
"datetime":"2012-04-11 06:38:37",
"depth":22.9,
"lat":2.311
},
{
"eqid":"2007hear",
"magnitude":8.4,
"lng":101.3815,
"src":"us",
"datetime":"2007-09-12 09:10:26",
"depth":30,
"lat":-4.5172
},
{
"eqid":"c00090da",
"magnitude":8.2,
"lng":92.4522,
"src":"us",
"datetime":"2012-04-11 08:43:09",
"depth":16.4,
"lat":0.7731
},
{
"eqid":"2007aqbk",
"magnitude":8,
"lng":156.9567,
"src":"us",
"datetime":"2007-04-01 18:39:56",
"depth":10,
"lat":-8.4528
},
{
"eqid":"2007hec6",
"magnitude":7.8,
"lng":100.9638,
"src":"us",
"datetime":"2007-09-12 21:49:01",
"depth":10,
"lat":-2.5265
},
{
"eqid":"a00043nx",
"magnitude":7.7,
"lng":100.1139,
"src":"us",
"datetime":"2010-10-25 12:42:22",
"depth":20.6,
"lat":-3.4841
},
{
"eqid":"2010utc5",
"magnitude":7.7,
"lng":97.1315,
"src":"us",
"datetime":"2010-04-06 20:15:02",
"depth":31,
"lat":2.3602
},
{
"eqid":"2009mebz",
"magnitude":7.6,
"lng":99.9606,
"src":"us",
"datetime":"2009-09-30 08:16:09",
"depth":80,
"lat":-0.7889
},
{
"eqid":"2009kdb2",
"magnitude":7.6,
"lng":92.9226,
"src":"us",
"datetime":"2009-08-10 17:55:39",
"depth":33.1,
"lat":14.0129
}
]
}
In the tutorial, based on the answers from @MДΓΓ БДLL and @Cody Caughlan , I was able to reformat the JSONFunctions.getJSONFromURL into a JSONArray instead of a JSONObject. Here is my modified working code, thank you!
public class JSONfunctions {
public static JSONArray getJSONfromURL(String url){
InputStream is = null;
String result = "";
JSONArray jArray = null;
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
is = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
jArray = new JSONArray(result);
return jArray;
}
}
You don't need to call json.getJSONArray() at all, because the JSON you're working with already is an array. So, don't construct an instance of JSONObject; use a JSONArray. This should suffice:
// ...
JSONArray json = new JSONArray(result);
// ...
for(int i=0;i<json.length();i++){
HashMap<String, String> map = new HashMap<String, String>();
JSONObject e = json.getJSONObject(i);
map.put("id", String.valueOf(i));
map.put("name", "Earthquake name:" + e.getString("eqid"));
map.put("magnitude", "Magnitude: " + e.getString("magnitude"));
mylist.add(map);
}
You can't use exactly the same methods as in the tutorial, because the JSON you're dealing with needs to be parsed into a JSONArray at the root, not a JSONObject.
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