在 Bash 中的单独行上打印数组元素? [英] Print array elements on separate lines in Bash?

问题描述

如何在单独的行上打印 Bash 数组的数组元素?这个方法有效，但肯定有更好的方法:

How do I print the array element of a Bash array on separate lines? This one works, but surely there is a better way:

$ my_array=(one two three)
$ for i in ${my_array[@]}; do echo $i; done
one
two
three

试过这个，但没有用:

$ IFS=$'\n' echo ${my_array[*]}
one two three

推荐答案

尝试这样做:

$ printf '%s\n' "${my_array[@]}"

$@ 和 $* 的区别:

• 未加引号，结果未指定.在 Bash 中，两者都扩展为单独的 args然后分词和通配.

• Unquoted, the results are unspecified. In Bash, both expand to separate args and then wordsplit and globbed.

引用，"$@" 将每个元素扩展为单独的参数，而 "$*"扩展为合并为一个参数的 args:"$1c$2c..."(其中 c 是IFS 的第一个字符).

Quoted, "$@" expands each element as a separate argument, while "$*" expands to the args merged into one argument: "$1c$2c..." (where c is the first char of IFS).

您几乎总是想要"$@"."${arr[@]}" 也是如此.

You almost always want "$@". Same goes for "${arr[@]}".

总是引用它们！

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