在 Bash 中将命令行参数转换为数组 [英] Convert command line arguments into an array in Bash

问题描述

如何将命令行参数转换为 bash 脚本数组?

How do I convert command-line arguments into a bash script array?

我想拿这个:

./something.sh arg1 arg2 arg3

并将其转换为

myArray=( arg1 arg2 arg3 )

以便我可以使用 myArray 在脚本中进一步使用.

so that I can use myArray for further use in the script.

之前的 SO 帖子很接近，但没有介绍如何创建数组:如何在 Bash 中解析命令行参数?

This previous SO post comes close, but doesn't go into how to create an array: How do I parse command line arguments in Bash?

我需要将参数转换为常规的 bash 脚本数组；我意识到我可以使用其他语言(例如 Python)，但需要在 bash 中执行此操作.我想我正在寻找附加"函数或类似的东西?

I need to convert the arguments into a regular bash script array; I realize I could use other languages (Python, for instance) but need to do this in bash. I guess I'm looking for an "append" function or something similar?

更新:我还想问如何检查零参数并分配默认数组值，感谢下面的答案，能够使这个工作:

UPDATE: I also wanted to ask how to check for zero arguments and assign a default array value, and thanks to the answer below, was able to get this working:

if [ "$#" -eq 0 ]; then
  myArray=( defaultarg1 defaultarg2 )
else
  myArray=( "$@" )
fi

推荐答案

实际上，您的命令行参数实际上就像一个数组.至少，您可以像对待数组一样对待 $@ 变量.也就是说，您可以将其转换为这样的实际数组:

Actually your command line arguments are practically like an array already. At least, you can treat the $@ variable much like an array. That said, you can convert it into an actual array like this:

myArray=( "$@" )

如果您只想输入一些参数并将它们输入到 $@ 值中，请使用 set:

If you just want to type some arguments and feed them into the $@ value, use set:

$ set -- apple banana "kiwi fruit"
$ echo "$#"
3
$ echo "$@"
apple banana kiwi fruit

了解如何使用参数结构在 POSIX sh 中特别有用，因为它没有任何其他像数组一样的东西.

Understanding how to use the argument structure is particularly useful in POSIX sh, which has nothing else like an array.

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