嵌套数组.第三层正在消失 [英] Nested array. Third level is disappearing
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问题描述
我有那个数组:
$a = array(
"7" => array(
"id" => 7,
"parent" => 6
),
"6" => array(
"id" => 6,
"parent" => 5
),
"5" => array(
"id" => 5,
"parent" => 4
),
"4" => array(
"id" => 4,
"parent" => 0
),
"3" => array(
"id" => 7,
"parent" => 2
),
"2" => array(
"id" => 7,
"parent" => 1
),
"1" => array(
"id" => 7,
"parent" => 0
)
);
我想要的结果是:
$a = array(
"4" => array(
"id" => 4,
"parent" => 0,
array(
"5" => array(
"id" => 5,
"parent" => 4,
array(
"6" => array(
"id" => 6,
"parent" => 5,
array(
"7" => array(
"id" => 7,
"parent" => 6
)
)
)
)
)
)
),
"2" => array(
"id" => 7,
"parent" => 1,
array(
"3" => array(
"id" => 7,
"parent" => 2
)
)
),
"1" => array(
"id" => 7,
"parent" => 0
)
);
我使用的代码是这样的:
the code that I use is this :
foreach($a as $v)
{
if(isset($a[$v['PARENT']]))
{
$a[$v['PARENT']][$v['ID']] = $v;
unset($a[$v['ID']]);
}
}
我遇到的问题是我得到了那个结果:
and the problem that I have is that I get that result :
$a = array(
"4" => array(
"id" => 4,
"parent" => 0,
array(
"5" => array(
"id" => 5,
"parent" => 4
)
)
),
"2" => array(
"id" => 7,
"parent" => 1,
array(
"3" => array(
"id" => 7,
"parent" => 2
)
)
),
"1" => array(
"id" => 7,
"parent" => 0
)
);
而不是需要它的结果.
推荐答案
要解决您的问题,您需要正确了解 PHP 中的变量引用/别名 有效.
To solve your problem you need to properly understand how variable referencing/aliasing in PHP works.
看看下面的示例代码,它看起来和你的没有太大区别,但利用引用来访问任何已经移动"的父级:
Look at the following example code, which does not look much different to yours but makes use of references in order to access any parent even it has already "moved":
# transform $flat into a tree:
foreach($flat as $id => &$value)
{
# check if there is a parent
if ($parentId = $value['parent'])
{
$flat[$parentId][0][$id] =& $value; # add child to parent
unset($flat[$id]); # remove reference from topmost level
}
}
unset($value); # remove iterator reference
print_r($flat); # your tree
$flat
现在包含来自 $flat
的所有值 - 但重新排序.演示.
$flat
now contains all values from $flat
- but reordered. Demo.
这篇关于嵌套数组.第三层正在消失的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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