在 TypeScript 中定义具有多种类型的数组 [英] Defining array with multiple types in TypeScript

问题描述

我有一个如下形式的数组:[ 1, "message" ].

我将如何在 TypeScript 中定义它?

解决方案

在 TypeScript 中定义多类型数组

使用联合类型(string|number)[] 演示:

const foo: (string|number)[] = [ 1, message";];

<块引用>

我有一个如下形式的数组:[ 1, message";].

如果你确定总是只有两个元素 [number, string] 那么你可以将它声明为一个元组:

const foo: [number, string] = [ 1, message";];

重要提示

当您想访问仅在其中一种类型上可用的属性时，这不适用于具有不同属性的复杂类型.

查看这个较新的答案.

I have an array of the form: [ 1, "message" ].

How would I define this in TypeScript?

解决方案

Defining array with multiple types in TypeScript

Use a union type (string|number)[] demo:

const foo: (string|number)[] = [ 1, "message" ];

I have an array of the form: [ 1, "message" ].

If you are sure that there are always only two elements [number, string] then you can declare it as a tuple:

const foo: [number, string] = [ 1, "message" ];

IMPORTANT NOTE

This won't work with complex types with different properties, when you want to access a property available on only one of the types.

See this newer answer.

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