在 C 中将 char 数组转换为 int 数 [英] Convert char array to a int number in C

问题描述

我想转换一个字符数组[]，例如:

I want to convert a char array[] like:

char myarray[4] = {'-','1','2','3'}; //where the - means it is negative

所以应该是整数:-1234在C 中使用标准 库.我找不到任何优雅的方法来做到这一点.

So it should be the integer: -1234 using standard libaries in C. I could not find any elegant way to do that.

我肯定可以附加\0".

I can append the '\0' for sure.

推荐答案

我个人不喜欢 atoi 功能.我建议 sscanf:

I personally don't like atoi function. I would suggest sscanf:

char myarray[5] = {'-', '1', '2', '3', '\0'};
int i;
sscanf(myarray, "%d", &i);

这是非常标准的，它在 stdio.h 库中 :)

It's very standard, it's in the stdio.h library :)

在我看来，它比 atoi 给你更多的自由，你的数字字符串的任意格式，并且可能还允许在末尾使用非数字字符.

And in my opinion, it allows you much more freedom than atoi, arbitrary formatting of your number-string, and probably also allows for non-number characters at the end.

编辑我刚刚在解释和比较的网站上发现了这个美妙的问题3 种不同的方法 - atoi、sscanf 和 strtol.此外，还有对 sscanf(实际上是整个 *scanf 函数系列)的更详细的了解.

EDIT I just found this wonderful question here on the site that explains and compares 3 different ways to do it - atoi, sscanf and strtol. Also, there is a nice more-detailed insight into sscanf (actually, the whole family of *scanf functions).

EDIT2看起来不仅仅是我个人不喜欢 atoi 功能.这是一个 链接 到一个解释 atoi 函数已被弃用，不应在较新的代码.

EDIT2 Looks like it's not just me personally disliking the atoi function. Here's a link to an answer explaining that the atoi function is deprecated and should not be used in newer code.

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