Javascript - 计算对象数组中的重复项并将计数存储为新对象 [英] Javascript - Counting duplicates in object array and storing the count as a new object
问题描述
我有一组作为产品的 javascript 对象.这些产品以购物车的形式显示在列表中.
我想根据 _.id
值计算数组中重复产品的数量,并从数组中删除这些对象,并将它们与更新版本和名为 count
带有此对象出现的总次数的值.
到目前为止,我已经尝试了很多方法并且我已经在谷歌上进行了搜索,但是我发现没有任何方法可以正确地完成这项工作.
我将使用的数组类型示例如下:
<预><代码>[{_id:5971df93bfef201237985c4d",弹头:5971df93bfef201237985c4d",税收百分比:23,总成本:9.99,货币:欧元",},]所以我希望我的最终结果是这样的 - 它删除了重复值并将其替换为相同的对象,但添加了一个名为 count 的新键,其值为对象最初的次数在数组中:
<预><代码>[{_id:5971df93bfef201237985c4d",弹头:5971df93bfef201237985c4d",税收百分比:23,总成本:9.99,货币:欧元",count: 2,//无论计数是多少},]到目前为止,我正在使用这种方法:
变量计数 = [];
if (cart.cart.products != undefined) {让 namestUi = {渲染名称(名称){返回 Array.from(names.reduce((计数器,对象)=>counters.set(object._id, (counters.get(object._id) || 0) + 1),新地图()),([对象,计数]) =>{var filterObj = names.filter(function(e) {返回 e._id == 对象;});返回({filterObj,计数})});}};count = namestUi.renderNames(cart.cart.products);控制台日志(计数)}
但它返回这样的值:
{filterObj: Array//重复的数组,计数:2}{filterObj:数组,计数:1}
并且由于我将 React-Native 与列表视图一起使用,因此这样的事情将不起作用.
它只需要按照之前的方式(一个数组)存储项目,但有一个名为 count
的新子项.
欢迎任何帮助!
我会坚持 reduce
,使用 Map
并传播它的 values
> 得到最终结果:
const names = [{ _id: 1 }, { _id: 1}, { _id: 2}, { _id: 1}];const 结果 = [...names.reduce( (mp, o) => {if (!mp.has(o._id)) mp.set(o._id, { ...o, count: 0 });mp.get(o._id).count++;返回 mp;}, new Map).values()];console.log(result);
或者,您可以先创建地图中所有计数为零的键(使用 Map 构造函数),然后再次迭代数据以更新计数器.这种任务拆分使代码比 reduce
更简洁:
const names = [{ _id: 1 }, { _id: 1}, { _id: 2}, { _id: 1}];const mp = new Map(names.map(o => [o._id, {...o, count: 0 }]));for (const {_id} of names) mp.get(_id).count++;const 结果 = Array.from(mp.values());console.log(result);
当您拥有多个键时,一种想法是使用 JSON.stringify([ ])
加入这些键:
const names = [{cat: 1, sub: 1}, {cat: 1, sub: 2}, {cat: 2,子:1},{猫:1,子:1}];const 结果 = [...names.reduce( (mp, o) => {const key = JSON.stringify([o.cat, o.sub]);if (!mp.has(key)) mp.set(key, { ...o, count: 0 });mp.get(key).count++;返回 mp;}, new Map).values()];console.log(result);
I have an array of javascript objects that are products. These products are displayed in a list as a cart.
I want to count the number of duplicate products in the array based in the _.id
value and remove these objects from the array and relace them with an updated version and a new key called count
with a value of the total number of times this object comes up.
So far, I have tried numerous methods and I've searched all over google but there's nothing that I've found that can do the job correctly.
An example of the type of array that I will be using would be this:
[
{ _id: "5971df93bfef201237985c4d",
slug: "5971df93bfef201237985c4d",
taxPercentage: 23,
totalCost: 9.99,
currency: "EUR",
},
]
so what I would want my end result to be would be something like this - it removes the duplicate value and replaces it with the same object but adds a new key called count with a value of the number of times the object initially was in the array:
[
{ _id: "5971df93bfef201237985c4d",
slug: "5971df93bfef201237985c4d",
taxPercentage: 23,
totalCost: 9.99,
currency: "EUR",
count: 2, // whatever the count is
},
]
So far I'm using this method:
var count = [];
if (cart.cart.products != undefined) {
let namestUi = {
renderNames(names){
return Array.from(
names.reduce( (counters, object) =>
counters.set(object._id, (counters.get(object._id) || 0) + 1),
new Map() ),
([object, count]) => {
var filterObj = names.filter(function(e) {
return e._id == object;
});
return ({filterObj, count})
}
);
}
};
count = namestUi.renderNames(cart.cart.products);
console.log(count)
}
but it returns the values like this:
{filterObj: Array // the array of the duplicates, count: 2}
{filterObj: Array, count: 1}
and since I am using React-Native with a list view something like this won't work.
It just needs to store the items the way it was before (an array) but with a new child called count
.
Any help is welcomed!
I would stick to reduce
, use a Map
and spread its values
to get the final result:
const names = [{ _id: 1 }, { _id: 1}, { _id: 2}, { _id: 1}];
const result = [...names.reduce( (mp, o) => {
if (!mp.has(o._id)) mp.set(o._id, { ...o, count: 0 });
mp.get(o._id).count++;
return mp;
}, new Map).values()];
console.log(result);
Or you can first create all the keys in the map with a zero count (using the Map constructor), and then iterate the data again to update the counter. This split of tasks makes the code more concise than with reduce
:
const names = [{ _id: 1 }, { _id: 1}, { _id: 2}, { _id: 1}];
const mp = new Map(names.map(o => [o._id, {...o, count: 0 }]));
for (const {_id} of names) mp.get(_id).count++;
const result = Array.from(mp.values());
console.log(result);
When you would have more than one key, then one idea is to join those with JSON.stringify([ ])
:
const names = [{cat: 1, sub: 1}, {cat: 1, sub: 2}, {cat: 2, sub: 1}, {cat: 1, sub: 1}];
const result = [...names.reduce( (mp, o) => {
const key = JSON.stringify([o.cat, o.sub]);
if (!mp.has(key)) mp.set(key, { ...o, count: 0 });
mp.get(key).count++;
return mp;
}, new Map).values()];
console.log(result);
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