在javascript中对周日到周六的对象进行排序 [英] sorting object Sunday to Saturday in javascript

问题描述

大家好，我知道这个问题被问了好几次，但我没有得到我的问题的确切答案.

Hello Everyone i know this question is asked several time but i am not getting exact answer to my question.

// I have array of object like this
data=[
        // "sunday": 1, // << sunday is first day of week      
      {DayOfWeek:"Saturday", TotalCount:30},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Sunday", TotalCount:18}, 
      {DayOfWeek:"Wednesday", TotalCount:20}        
    ];


// I need sorted like this:
data=[
        // "sunday": 1, // << sunday is first day of week
      {DayOfWeek:"Sunday", TotalCount:18},  
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Wednesday", TotalCount:20},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Saturday", TotalCount:30}  
    ];

我尝试了这个，但无法获得预期的结果.它通过像

I tried this one but I am not able to get the expected result. it is giving me a sorted array by starting alphabet like

周五、周六.

var 排序器 = {//"sunday": 1,//<<星期日是一周的第一天星期日":1，星期一":2，星期二":3，星期三":4，星期四":5，星期五":6，星期六":7}

var sorter = { // "sunday": 1, // << sunday is first day of week "sunday": 1, "monday": 2, "tuesday": 3, "wednesday": 4, "thursday": 5, "friday": 6, "saturday": 7 }

  var result= data.sort(function sortByDay(a, b) {
    var day1 = a.DayOfWeek.toLowerCase();
    var day2 = b.DayOfWeek.toLowerCase();
    return sorter[day1] > sorter[day2];
  });

请帮助我，提前致谢.

推荐答案

您可以使用订单的对象对其进行排序，就像您已经拥有的那样，但您需要区别

You can sort it with an object for the order, as you already had, but you need the difference

return order[a.DayOfWeek] - order[b.DayOfWeek];

作为排序回调的返回值.

as a return value for the sort callback.

var data = [{ DayOfWeek: "Saturday", TotalCount: 30 }, { DayOfWeek: "Friday", TotalCount: 10 }, { DayOfWeek: "Monday", TotalCount: 23 }, { DayOfWeek: "Sunday", TotalCount: 18 }, { DayOfWeek: "Wednesday", TotalCount: 20 }],
    order = { Sunday: 1, Monday: 2, Tuesday: 3, Wednesday: 4, Thursday: 5, Friday: 6, Saturday: 7 };

data.sort(function (a, b) {
    return order[a.DayOfWeek] - order[b.DayOfWeek];
});
document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>');

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