为什么我不能在 JS 中复制这个二维数组?如何制作副本? [英] Why can't I make a copy of this 2d array in JS? How can I make a copy?
问题描述
我正在实施 John Conway Game of Life,但我遇到了一个奇怪的问题.如果代码给我带来麻烦,这里是一个简短的版本:
I'm implementing a John Conway Game of Life, but I'm having a weird problem. Here is a short version if the code giving me trouble:
let lifeMap = [
[true, false, false],
[false, false, false],
[false, false, false]
];
let oldLifeMap = lifeMap.slice();
for (let row = 0; row < lifeMap.length; row++) {
for (let val = 0; val < lifeMap[row].length; val++) {
let bool = lifeMap[row][val];
let newBool = false; // here is where I would determine if cell is alive/dead
lifeMap[row][val] = newBool;
if (row === 0 && val === 0) console.log("at (0,0)", oldLifeMap[0][0]);
}
}
响应此代码,JavaScript 打印 at (0,0) false
.我需要它保持 true
直到下一代开始.
In response to this code, JavaScript prints at (0,0) false
. I need it to stay true
until the next generation starts.
我认为做 let oldLifeMap = lifeMap.slice()
会解决它,但它没有,我不知道为什么.(难道不应该复制二维数组而不是创建第二个引用吗?)
I thought doing let oldLifeMap = lifeMap.slice()
would fix it, but it doesn't, and I'm not sure why. (Shouldn't it copy the 2d array and not create a second ref to it?)
无论如何,这里发生了什么,我如何在此处成功制作 lifeMap
的实际副本?
Anyway, what is going on here, and how do I successfully make an actual copy of lifeMap
here?
推荐答案
@Redu's answer 的提示对 N 维数组很有用,但特别是在 2D 数组的情况下,是不必要的.为了深度克隆您的特定二维数组,您需要做的就是:
A hat-tip to @Redu's answer which is good for N-dimensional arrays, but in the case of 2D arrays specifically, is unnecessary. In order to deeply clone your particular 2D array, all you need to do is:
let oldLifeMap = lifeMap.map(inner => inner.slice())
这将使用不带参数的 .slice()
创建每个内部数组的副本,并将其存储到使用 .map()
.
This will create a copy of each inner array using .slice()
with no arguments, and store it to a copy of the outer array made using .map()
.
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