Bash，参数列表段 [英] Bash, argument list segment

问题描述

如果你在 python 中有一个列表，并且你希望从 2 到 n 的元素可以做一些像

If you have a list in python, and you want the elements from 2 to n can do something nice like

list[2:]

我想在 Bash 中使用类似于 argv 的东西.我想将所有元素从 $2 传递给 argc 给一个命令.我目前有

I'd like to something similar with argv in Bash. I want to pass all the elements from $2 to argc to a command. I currently have

command $2 $3 $4 $5 $6 $7 $8 $9

但这不够优雅.会是正确"的方式吗?

but this is less than elegant. Would would be the "proper" way?

推荐答案

你也可以切片"，$@ 获取 bash 中的所有参数.

you can do "slicing" as well, $@ gets all the arguments in bash.

echo "${@:2}"

从第二个参数开始

例如

$ cat shell.sh
#!/bin/bash
echo "${@:2}"

$ ./shell.sh 1 2 3 4
2 3 4

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