检查一个数组是否包含另一个数组的所有元素 [英] Checking if an array contains all elements of another array

问题描述

我正在设计一个电气工程应用程序.但是，我坚持这一点:我有以下数组

I'm designing an electrical engineering application. However, i'm stuck on this: I have the following array

<?php 
// Static Array
$GroupOfEight = array (
                      array(0,1,3,2,4,5,7,6),
                      array(4,5,6,7,16,12,13,14),
                      array(12,13,15,14,8,9,11,10),
                      array(2,6,14,10,3,7,15,11),
                      array(1,3,5,7,13,15,9,11),
                      array(0,4,12,8,1,5,13,9),
                      array(0,1,3,2,8,9,11,10)
                      );
?>

我还有另一个数组，但这个数组是一维的.

And I have another array, but this one is one dimensional.

<?php
$myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method.
?>

我想要做的是检查 $myStack 是否等于 $GroupOfEight 数组的任何子数组.(数字排序并不重要.脚本应该只检查是否包含每个元素.它们的顺序是否相同并不重要.)

What I want to do is to check if $myStack is equal to any sub array of $GroupOfEight array. ( Number ordering is not important. The script should just check if every elements contained. It's not important if their order is same or not. )

这是我目前为解决这个问题所做的工作:

Here is what I've done to solve the issue so far:

<?php
//Check if stackArray contains 8group
for($i=0; $i<count($GroupOfEight);$i++)
for($j=0; $j<count($GroupOfEight[$i]); $j++){
    //$containsSearch = count(array_intersect($search_this,$all)) == count($search_this);
    $containsSearch = count(array_intersect($stackArray,$GroupOfEight[$j])) == count($stackArray);
    echo $containsSearch;
}
?>

请帮我更正我的代码或向我介绍这个问题的解决方案，谢谢.

Please help me correct my code or introduce me the solution of this issue, Thanks.

它应该只给出 1 个索引号.例如 stackArray 是 0,1,3,2,4,1,2,3 并且它应该找到匹配相同数字的 GroupOfEight[N]，而不管数字的顺序如何.如果有匹配的情况，我应该得到 N.

It should give only 1 index number. for example stackArray is 0,1,3,2,4,1,2,3 and it should find GroupOfEight[N] that matches the same numbers, regardless of the order of the numbers. I should get the N if there is a matching case.

推荐答案

给定您的示例数组，输出将是:

Given your sample arrays, the output of this will be:

> 0

如果您必须只有一个数字输出，则应该这样做:

In case you HAD to have only one number output, this should do that:

<?php
//Check if stackArray contains 8group
$check=false;
for($i=0; $i<count($GroupOfEight);$i++){
    //$containsSearch = count(array_intersect($search_this,$all)) == count($search_this);
    $containsSearch = (count(array_intersect($stackArray,$GroupOfEight[$i])) == count($stackArray) && count(array_intersect($stackArray,$GroupOfEight[$i])) == count($GroupOfEight[$i]));
    if($containsSearch && !$check){
        echo $i; //This specifies which index in GroupOfEight contains a matching array
        $check=true;
    }
}
?>

做了一个功能.返回第一个匹配的索引或 -1 没有匹配:

Made a function. Returns first matched index or -1 for no matches:

function searcheight($stackArray,$GroupOfEight){
    for($i=0; $i<count($GroupOfEight);$i++){
        $containsSearch = (count(array_intersect($stackArray,$GroupOfEight[$i])) == count($stackArray) && count(array_intersect($stackArray,$GroupOfEight[$i])) == count($GroupOfEight[$i]));
        if($containsSearch){
            return $i; //This specifies which index in GroupOfEight contains a matching array
        }
    }
    return -1;
}
echo searcheight($stackArray,$GroupOfEight);

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