在 C# 中将一个 byte[] 拆分为多个 byte[] 数组 [英] Splitting a byte[] into multiple byte[] arrays in C#
问题描述
我正在尝试分块"图像的字节.这将允许我分部分上传大图像.我将图像当前存储为一个大字节 [].我想将字节数组拆分为 byte[]
,最大长度为 512 个元素.但是,我不确定如何以最有效的方式执行此操作.
I am trying to "chunk" up the bytes of an image. This will allow me to upload a large image in portions. I have the image currently stored as one large byte[]. I would like to split the byte array into byte[]
's with a maxlength of 512 elements. However, I'm not sure how to do this in the most efficient way.
有谁知道我如何以最有效的方式做到这一点?
Does anyone know how I can do this in the most efficient manner?
推荐答案
最有效的方法是:不要.如果您已经将图像作为单个字节 [] 那么对于本地代码,只需指定偏移量和长度(可能是 ArraySegment-of-byte)通常就足够了.如果你的上传 API 只接受 byte[],那么你仍然不应该把它完全分块;只需使用单个 512 缓冲区并使用 Buffer.BlockCopy 将其加载到连续的数据块中.您可能需要调整 (Array.Resize) final 块的大小,但最多需要 2 个数组.
The most efficient method would be: not to. If you already have the image as a single byte[] then for local code, just specifying the offset and length (perhaps som ArraySegment-of-byte) is usually sufficient. If your upload API only takes byte[], then you still shouldn't chunk it completely; just use a single 512 buffer and use Buffer.BlockCopy to load it will successive pieces of the data. You may need to resize (Array.Resize) the final chunk, but at most 2 arrays should be needed.
更好;首先避免需要 byte[]:考虑通过流 API 加载数据(如果数据来自文件,这将工作得很好);只需使用 Read(在循环中,处理返回值等)来填充最大 512 的块.例如(未经测试,仅用于说明):
Even better; avoid needing a byte[] in the first place: consider loading the data via a streaming API (this will work well if the data is coming from a file); just use Read (in a loop, processing the returned value etc) to populate chunks of max 512. For example (untested, just of illustration):
byte[] buffer = new byte[512];
while(true) {
int space = 512, read, offset = 0;
while(space > 0 && (read = stream.Read(buffer, offset, space)) > 0) {
space -= read;
offset += read;
}
// either a full buffer, or EOF
if(space != 0) { // EOF - final
if(offset != 0) { // something to send
Array.Resize(red buffer, offset);
Upload(buffer);
}
break;
} else { // full buffer
Upload(buffer);
}
}
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