从python中的多维数组中删除重复条目 [英] removing duplicate entries from multi-d array in python

问题描述

我有一个二维数组

 xx=[[a,1],[b,2],[c,3]]

现在我正在尝试从中删除重复的条目.对于简单的一维数组，简单的代码如

xx=list(set(xx))

会起作用.但是在二维元素上尝试设置会出错

temp = set(xx)类型错误:不可散列的类型:列表"

一种解决方法是序列化 xx 个元素，然后在新数组上执行 list(set())，然后再次反序列化所有元素.

python 有什么解决办法吗?

解决方案

将元素转换为元组，然后使用set.

<预><代码>>>>xx=[['a',1],['b',2],['c',3],['c',3]]>>>set(tuple(element) for element in xx)set([('a', 1), ('b', 2), ('c', 3)])>>>

与列表不同，元组可以散列.因此.完成后，将元素转换回列表.将所有内容放在一起:

<预><代码>>>>[list(t) for t in set(tuple(element) for element in xx)][['a', 1], ['b', 2], ['c', 3]]

I have a 2-d array

 xx=[[a,1],[b,2],[c,3]]

Now I'm trying to remove duplicate entries from it. For simple 1-D array, simple code like

xx=list(set(xx))

would work. But trying set on 2-d elements gives an error

temp = set(xx)
TypeError: unhashable type: 'list'

One workaround would be to serialize xx elements, and then do a list(set()) on new array and then unserialize all the elements back again.

Is there any solution in python?

解决方案

Convert elements to tuple and then use set.

>>> xx=[['a',1],['b',2],['c',3],['c',3]]
>>> set(tuple(element) for element in xx)
set([('a', 1), ('b', 2), ('c', 3)])
>>> 

Tuples, unlike lists, can be hashed. Hence. And once you are done, convert the elements back to list. Putting everything together:

>>> [list(t) for t in set(tuple(element) for element in xx)]
[['a', 1], ['b', 2], ['c', 3]]

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