如何使用python从数组中删除特定元素 [英] How to remove specific element from an array using python
问题描述
我想写一些从数组中删除特定元素的东西.我知道我必须 for 循环遍历数组才能找到与内容匹配的元素.
假设我有一组电子邮件，我想删除与某个电子邮件字符串匹配的元素.
我实际上想使用 for 循环结构，因为我也需要对其他数组使用相同的索引.
这是我拥有的代码:
用于索引，电子邮件中的项目:如果电子邮件[索引] == 'something@something.com':emails.pop(索引)otherarray.pop(索引)您不需要迭代数组.只是:
<预><代码>>>>x = ['ala@ala.com', 'bala@bala.com']>>>X['ala@ala.com', 'bala@bala.com']>>>x.remove('ala@ala.com')>>>X['bala@bala.com']这将删除与字符串匹配的第一个出现.
编辑后，您仍然不需要迭代.就这样做:
index = initial_list.index(item1)del initial_list[索引]del other_list[索引]I want to write something that removes a specific element from an array. I know that I have to for loop through the array to find the element that matches the content.
Let's say that I have an array of emails and I want to get rid of the element that matches some email string.
I'd actually like to use the for loop structure because I need to use the same index for other arrays as well.
Here is the code that I have:
for index, item in emails:
if emails[index] == 'something@something.com':
emails.pop(index)
otherarray.pop(index)
You don't need to iterate the array. Just:
>>> x = ['ala@ala.com', 'bala@bala.com']
>>> x
['ala@ala.com', 'bala@bala.com']
>>> x.remove('ala@ala.com')
>>> x
['bala@bala.com']
This will remove the first occurence that matches the string.
EDIT: After your edit, you still don't need to iterate over. Just do:
index = initial_list.index(item1)
del initial_list[index]
del other_list[index]
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