在 C 中 - 检查字符数组中是否存在字符 [英] In C - check if a char exists in a char array

问题描述

我正在尝试检查一个字符是否属于无效字符列表/数组.

I'm trying to check if a character belongs to a list/array of invalid characters.

来自 Python 背景，我曾经只能说:

Coming from a Python background, I used to be able to just say :

for c in string:
    if c in invalid_characters:
        #do stuff, etc

如何使用常规 C 字符数组执行此操作?

How can I do this with regular C char arrays?

推荐答案

等效的 C 代码如下所示:

The equivalent C code looks like this:

#include <stdio.h>
#include <string.h>

// This code outputs: h is in "This is my test string"
int main(int argc, char* argv[])
{
   const char *invalid_characters = "hz";
   char *mystring = "This is my test string";
   char *c = mystring;
   while (*c)
   {
       if (strchr(invalid_characters, *c))
       {
          printf("%c is in \"%s\"\n", *c, mystring);
       }

       c++;
   }

   return 0;
}

注意 invalid_characters 是一个 C 字符串，即.一个以 null 结尾的 char 数组.

Note that invalid_characters is a C string, ie. a null-terminated char array.

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