在php中检查数组是否为空 [英] Check If array is null or not in php

问题描述

我有一个像下面这样的数组，它是通过解析 xml url 生成的.

I have an array like below which is generated by parsing a xml url.

数组是

Array
  (
 [Tags] => SimpleXMLElement Object
    (
        [0] => 

    )
  )

数组名是$result.现在我想检查数组是否像上面那样接收到我想打印一条失败消息.但是如何在 if 条件下检查这个数组?

The array name is $result. Now I want to check that if the array received like above I want to print a message of failure. But how to check this array in if condition?

推荐答案

你可以使用

empty($result) 

检查主数组是否为空.

但是由于您有一个 SimpleXMLElement 对象，您需要查询该对象是否为空.请参阅 http://www.php.net/manual/en/simplexmlelement.count.php

But since you have a SimpleXMLElement object, you need to query the object if it is empty or not. See http://www.php.net/manual/en/simplexmlelement.count.php

例如:

if (empty($result) || !isset($result['Tags'])) {
    return false;
}
if ( !($result['Tags'] instanceof SimpleXMLElement)) {
    return false;
}
return ($result['Tags']->count());

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