使用 JAXB 将 JSON 编组/解组为 Java 类 [英] Marshall/Unmarshall a JSON to a Java class using JAXB

问题描述

我使用 JAX-RS 和 JAXB 注释成功地将 POJO 封送到 JSON.

I am successfully marshaling a POJO into JSON using JAX-RS and JAXB annotations.

问题是，当我尝试使用它来解组我的请求时，它不起作用.据我在 文档 JAX-RS 可以自动将应用程序/json 字符串编组和解组回 java 类.

The problem is that when I am trying to use the same for un-marshalling my request it doesn’t work. As far as I can see in the documentation JAX-RS can automatically marshal and unmarshal application/json strings back to java classes.

我是否需要为此创建我自己的 MessageBodyReader，或者框架支持而不使用 Jackson 库?

Do I need to create my own MessageBodyReader for that, or this is supported by the framework without using Jackson libraries?

推荐答案

编组到 XML 很容易，但我花了一段时间才弄清楚如何编组到 JSON.找到解决方案后很简单.

Marshalling to XML is easy, but it took me a while to figure out how to marshall to JSON. Pretty simple after you find the solution though.

public static String marshalToXml( Object o ) throws JAXBException {

    StringWriter writer = new StringWriter();
    Marshaller marshaller = JAXBContext.newInstance( o.getClass() ).createMarshaller();
    marshaller.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, true );
    marshaller.marshal( o, writer );
    return writer.toString();
}

public static String marshalToJson( Object o ) throws JAXBException {

    StringWriter writer = new StringWriter();
    JAXBContext context = JSONJAXBContext.newInstance( o.getClass() );

    Marshaller m = context.createMarshaller();
    JSONMarshaller marshaller = JSONJAXBContext.getJSONMarshaller( m );
    marshaller.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, true );
    marshaller.marshallToJSON( o, writer );
    return writer.toString();
}

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