为什么 JAXB 生成的类具有受保护的成员,我该如何更改? [英] Why do JAXB generated classes have protected members and how can I change this?
问题描述
我一直在互联网上搜索 JAXB 生成的类具有受保护成员的原因(所有这些成员,无论继承如何).
I have been searching the internet for a reason why JAXB generated classes have protected members (all of them, regardless of inheritance).
我希望成员是私人的.
我的搜索结果为空.
我有普通的 xsd 文件,它们使用 Maven 和 JAXB 转换为 Java 类.理想情况下,生成的成员应该是私有的,但我找不到实现这一点的方法.
I have normal xsd files which are converted into Java classes using Maven and JAXB. Ideally the generated members should be private but I cannot find a way to achieve this.
有没有办法修改这个默认行为?
Is there a way to modify this default behaviour?
推荐答案
好吧,我要回答我自己的问题.创建插件是正确的方法.
Well, I am going to respond to my own question. Creating a plugin was the right way to go.
我编写了以下插件,它似乎有效.
I wrote the following plugin and it seems to work.
public class PrivateMemberPlugin
extends Plugin
{
@Override
public String getOptionName()
{
return "Xpm";
}
@Override
public String getUsage()
{
return " -Xpm : Change members visibility to private";
}
@Override
public boolean run(Outline model, Options opt, ErrorHandler errorHandler)
throws SAXException
{
for (ClassOutline co : model.getClasses())
{
JDefinedClass jdc = co.implClass;
// avoid concurrent modification by copying the fields in a new list
List<JFieldVar> fields = new ArrayList<JFieldVar>(jdc.fields().values());
for (JFieldVar field : fields)
{
// never do something with serialVersionUID if it exists.
if (!field.name().equalsIgnoreCase("serialVersionuid"))
{
// only try to change members that are not private
if (field.mods().getValue() != JMod.PRIVATE)
{
// since there is no way to change the visibilty, remove the field an recreate it
jdc.removeField(field);
jdc.field(JMod.PRIVATE, field.type(), field.name());
}
}
}
}
return true;
}
}
如果你愿意,可以随意使用它.
Feel free to use this if you want.
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