PHP PDOException:“SQLSTATE[HY093]:无效的参数号"； [英] PHP PDOException: "SQLSTATE[HY093]: Invalid parameter number"

问题描述

当我尝试运行以下函数时收到错误SQLSTATE[HY093]: Invalid parameter number":

I'm getting the error "SQLSTATE[HY093]: Invalid parameter number" when I try to run the below function:

function add_persist($db, $user_id) {
    $hash = md5("per11".$user_id."sist11".time());
    $future = time()+(60*60*24*14);
    $sql = "INSERT INTO persist (user_id, hash, expire) VALUES (:user_id, :hash, :expire) ON DUPLICATE KEY UPDATE hash=:hash";
    $stm = $db->prepare($sql);
    $stm->execute(array(":user_id" => $user_id, ":hash" => $hash, ":expire" => $future));
    return $hash;
}

我觉得这很简单，我只是没有抓住.有什么想法吗?

I feel like it's something simple that I'm just not catching. Any ideas?

推荐答案

尝试:

$sql = "INSERT INTO persist (user_id, hash, expire)
        VALUES (:user_id, :hash, :expire)
        ON DUPLICATE KEY UPDATE hash=:hash2";

和

$stm->execute(
    array(":user_id" => $user_id, 
          ":hash" => $hash, 
          ":expire" => $future,
          ":hash2" => $hash)
);

文档摘录(http://php.net/manual/en/pdo.prepare.php):

当您调用 PDOStatement::execute() 时，您必须为希望传递给语句的每个值包含一个唯一的参数标记.您不能在准备好的语句中两次使用同名的命名参数标记.不能将多个值绑定到单个命名参数，例如 SQL 语句的 IN() 子句.

You must include a unique parameter marker for each value you wish to pass in to the statement when you call PDOStatement::execute(). You cannot use a named parameter marker of the same name twice in a prepared statement. You cannot bind multiple values to a single named parameter in, for example, the IN() clause of an SQL statement.

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