净C＃到PHP铅与byte []数组和放大器; ComputeHash [英] .Net C# to PHP Pb with byte[] array & ComputeHash

问题描述

我在净C＃这个功能，想用PHP做相同的。但我不明白，所有的C＃的一部分，不知道我的code。

i have this function in .Net C# and want to do the same in PHP. But i don't understand all C# part and not sure about my code.

public static string getMD5Hash(string input)
{
    MD5 mD = new MD5CryptoServiceProvider();
    byte[] array = Encoding.UTF8.GetBytes(input);
    array = mD.ComputeHash(array);
    StringBuilder stringBuilder = new StringBuilder();
    int i = 0;
    byte[] array2 = array;
    int length = array2.Length;
    while (i < length)
    {
        stringBuilder.Append(array2[i].ToString("x2").ToLower());
        i++;
    }
    return stringBuilder.ToString();
}

我已经找到谁介绍了如何从一个字符串（谁是相同的）创建MD5哈希的为例此处的 http://en.csharp-online.net/Create_a_MD5_Hash_from_a_string

和发现的SOF后约字符串字节：字符串字节数组在PHP

And found the SoF post about String to Byte : String to byte array in php

所以在这里我所做的只是为了让一些测试：

So here what i've done just to make some test :

function getMD5Hash($input){


for($i = 0; $i < strlen($input); $i++){

    $char = substr($input,$i,1);
    $hex_ary[] = sprintf("%02X", ord($char));}


$TheMD5=md5(implode('',$hex_ary));

for($i = 0; $i < strlen($TheMD5); $i++){

    $char = substr($TheMD5,$i,1);
    $Sec_hex_ary[] .= sprintf("%02X", ord($char));}


$StringBuilder ='';
$i = 0;
$Thelength = count($Sec_hex_ary);

while ($i < $Thelength)
{
    $stringBuilder .= strtolower(sprintf("%02X", ord($Sec_hex_ary[$i])));
    $i++;
}

return $stringBuilder;}

所以，我的理解（我希望好）：

So what i understand (i hope good) :

1. 第一步拨打MD5提供商。 PHP =>不需要
2. 然后创建一个数组的byte []''阵'谁包含以字节为单位输入重新presentation。
3. 然后连接code在MD5'阵'。
4. 创建一个新的字符串。
5. 然后创建一个阵'的byte []''ARRAY2谁包含数组
6. 在随后追加的字符串再以小写字节presentation字符串。
7. 返回字符串。

我错了？如果是（当然）你能解释一下我吗？

Am i wrong ? if yes (certainly) can you explain me ?

那么，它给我：回声getMD5Hash（'1ca48ad63d48c3adfae0d7af77f27027'）;

So what it give me : "echo getMD5Hash('1ca48ad63d48c3adfae0d7af77f27027'); "

的print_r（$ hex_ary）=

Print_r($hex_ary) =

Array
(
    [0] => 31
    [1] => 63
    [2] => 61
    [3] => 34
    [4] => 38
    [5] => 61
    [6] => 64
    [7] => 36
    [8] => 33
    [9] => 64
    [10] => 34
    [11] => 38
    [12] => 63
    [13] => 33
    [14] => 61
    [15] => 64
    [16] => 66
    [17] => 61
    [18] => 65
    [19] => 30
    [20] => 64
    [21] => 37
    [22] => 61
    [23] => 66
    [24] => 37
    [25] => 37
    [26] => 66
    [27] => 32
    [28] => 37
    [29] => 30
    [30] => 32
    [31] => 37
)

回声$ TheMD5;

echo $TheMD5;

=> 418868f1137ea82935bbd235133993cf

的print_r（$ Sec_hex_ary）;

print_r($Sec_hex_ary);

Array
(
    [0] => 34
    [1] => 31
    [2] => 38
    [3] => 38
    [4] => 36
    [5] => 38
    [6] => 66
    [7] => 31
    [8] => 31
    [9] => 33
    [10] => 37
    [11] => 65
    [12] => 61
    [13] => 38
    [14] => 32
    [15] => 39
    [16] => 33
    [17] => 35
    [18] => 62
    [19] => 62
    [20] => 64
    [21] => 32
    [22] => 33
    [23] => 35
    [24] => 31
    [25] => 33
    [26] => 33
    [27] => 39
    [28] => 39
    [29] => 33
    [30] => 63
    [31] => 66
)

和回声给我：3333333333333633333333363633333333333636363333333333333333333636

And the echo give me : 3333333333333633333333363633333333333636363333333333333333333636

你认为这是正确的？感谢您的帮助。

do you think this is correct ? Thanks for the help.

推荐答案

• 在PHP的字节数组是字符串，没有必要用实际阵列
• 如果您的字符串已经是EN codeD的UTF-8，有没有必要等同于 Encoding.UTF8.GetBytes（输入）线;如果不是，使用 的iconv
• 在PHP中的 MD5 已返回一个十六进制字符串，没有必要从原始输出构建一个

• PHP's "byte arrays" are strings, no need to use actual arrays
• if your string is already encoded in UTF-8, there's no necessary equivalent to the Encoding.UTF8.GetBytes(input) line; if it is not, convert it using iconv
• PHP's md5 already returns a hex string, no need to build one from the raw output

总之，相当于C＃功能的PHP大概是：

Altogether, the PHP equivalent to that C# function is probably:

echo md5($input);

说了这么多，有可能是关于C＃避开了我在这里，可能会改变结果错综复杂。

Having said that, there may be intricacies about C# that elude me here that may change the result.

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