如何使用 Gradle 和 Android Studio 从资源中排除文件? [英] How to exclude file from resources using Gradle and Android Studio?

问题描述

我的项目中有一个生成的字符串资源 xml 文件，该文件是从扩展名为 .template 的文件生成的.我试图从构建中排除这个模板，因为它给了我重复的资源错误.以下对我不起作用，我被卡住了:

I have a generated string resource xml file in my project which is generated from a file with a .template extension. I'm trying to exclude this template from the build since it gives me duplicate resource error. The following does not work for me and I'm stuck:

  sourceSets {
       main {
           manifest.srcFile 'AndroidManifest.xml'
           java.srcDirs = ['src']
           resources.srcDirs = ['res']
           resources.exclude '**/build_id.template'
           res.srcDirs = ['res']
           res.exclude '**/build_id.template'
           assets.srcDirs = ['assets']
       }
   }

错误:

Error:Error: Duplicate resources: <project-dir>/res/values/build_id.template:string/build_id, <project-dir>/res/values/build_id.xml:string/build_id

如何正确排除特定资源文件?

How can I exclude a particular resource file properly?

推荐答案

为了其他在您项目上工作的人的理智，我强烈建议您不要将模板(输入)和自动生成的文件(输出)放在同一目录中.您可以创建自己的独立模板"目录，以防止其包含在您的构建中.

For the sanity of other folks working on your project, I strongly discourage putting templates (input) and auto-generated files (output) in the same directory. You could create your own, independent 'templates' directory to keep it from being included in your build.

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