比较两个列表并删除相同的最有效方法 [英] Most efficient way to compare two lists and delete the same

问题描述

我想比较两个列表并将有效单词放入一个新列表中.

I want to compare two lists and get the valid words into a new list.

var words = new List<string>();
var badWords = new List<string>();

//this is just an example list. actual list does contain 700 records
words.Add("Apple");
words.Add("Moron");
words.Add("Seafood");
words.Add("Cars");
words.Add("Chicken");
words.Add("Twat");
words.Add("Watch");
words.Add("Android");
words.Add("c-sharp");
words.Add("Fool");

badWords.Add("Idiot");
badWords.Add("Retarded");
badWords.Add("Twat");
badWords.Add("Fool");
badWords.Add("Moron");

我正在寻找最有效的方法来比较列表并将所有好"词放入新列表中.finalList 不应包含Moron"、Twat"和Fool".

I am looking for most efficient way to compare the lists and put all the 'good' words into a new list. The finalList shouldn't contain "Moron", "Twat" and "Fool".

var finalList = new List<string>();

还是不需要新建List?我很高兴听到你的想法！

Or is it unnecessary to create a new List? I am happy to hear your ideas!

提前致谢

推荐答案

Use EnumerableExcept 函数存储在 System.Linq 命名空间

Use EnumerableExcept function storing in System.Linq namespace

finalList = words.Except(badWords).ToList();

节省时间的最有效方法也是最快的方法，因为Except 实现使用Set，速度很快

Most efficient way to save your time and also the fastest way to do it, because Except implementation uses Set, which is fast

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