如何将纬度和经度映射到 3D 球体 [英] how to map latitude and longitude to a 3D Sphere

问题描述

尝试将经纬度坐标映射到 3d 球体上.

Trying to map coordinates with latitude and longitude onto a 3d sphere.

我从互联网上尝试了三组不同的方程式，但都没有奏效.有谁知道怎么做.

I've tried three different sets of equations from the internet and none of them work. Does anyone know how to do it.

这些是我试过但没有用的.

These are the ones I tried that didn't work.

var phi   = (90-lat)*(Math.PI/180),
theta = (lon+180)*(Math.PI/180),
x = -((radius) * Math.sin(phi)*Math.cos(theta)),
z = ((radius) * Math.sin(phi)*Math.sin(theta)),
y = ((radius) * Math.cos(phi));

return new THREE.Vector3(x,y,z);


  var height = 600;
  var phi = (lat)*Math.PI/180;
  var theta = (lon-180)*Math.PI/180;

  var x = -(radius+height) * Math.cos(phi) * Math.cos(theta);
  var y = (radius+height) * Math.sin(phi);
  var z = (radius+height) * Math.cos(phi) * Math.sin(theta);

  return new THREE.Vector3(x,y,z);



 var x = Math.cos(lon) * Math.sin(lat),
     y = Math.sin(lon) * Math.sin(lat),
     z = Math.cos(lat);
 return  new THREE.Vector3(x,y,z);

推荐答案

嗯，这个确实有效！

var phi   = (90-lat)*(Math.PI/180),
theta = (lon+180)*(Math.PI/180),
x = -((radius) * Math.sin(phi)*Math.cos(theta)),
z = ((radius) * Math.sin(phi)*Math.sin(theta)),
y = ((radius) * Math.cos(phi));

return new THREE.Vector3(x,y,z);

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