将 64 位数组转换为 Int64 或 ulong C# [英] Convert 64 bits array into Int64 or ulong C#
问题描述
我有一个 int 位数组(长度始终为 64),例如:
I have an int array of bits (length always 64) like:
1110000100000110111001000001110010011000110011111100001011100100
我想把它写在一个 Int64
(或 ulong?)变量中.怎么做?
and I want to write it in one Int64
(or ulong?) variable. How to do it?
我尝试创建一个 BitArray
然后获取 int
,但它在 CopyTo 行上抛出 System.ArgumentException
:
I tried to create a BitArray
and then get int
, but it throws System.ArgumentException
, on CopyTo line:
private static Int64 GetIntFromBitArray(BitArray bitArray) {
var array = new Int64[1];
bitArray.CopyTo(array, 0);
return array[0];
}
推荐答案
那是因为如文档,
指定的数组必须是兼容的类型.仅支持 bool、int 和 byte 类型的数组.
The specified array must be of a compatible type. Only bool, int, and byte types of arrays are supported.
所以你可以这样做:(未测试)
So you could do something like this: (not tested)
private static long GetIntFromBitArray(BitArray bitArray)
{
var array = new byte[8];
bitArray.CopyTo(array, 0);
return BitConverter.ToInt64(array, 0);
}
查看BitArray.CopyTo
的实现,将位复制到int[]
(然后构建long
)会更快代码>从它的两半),可能看起来像这样:(也未测试)
Looking at the implementation of BitArray.CopyTo
, it would be faster to copy the bits into an int[]
(and then build the long
from its two halves), that could look something like this: (also not tested)
private static long GetIntFromBitArray(BitArray bitArray)
{
var array = new int[2];
bitArray.CopyTo(array, 0);
return (uint)array[0] + ((long)(uint)array[1] << 32);
}
转换为 uint
是为了防止符号扩展.
Casts to uint
are to prevent sign-extension.
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