TypeScript 中的抽象构造函数类型 [英] Abstract constructor type in TypeScript

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本文介绍了TypeScript 中的抽象构造函数类型的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

TypeScript 中非抽象类(非抽象构造函数)的类型签名如下:

声明类型 ConstructorFunction = new (...args: any[]) =>任何;

这也称为 newable 类型.但是,我需要一个 abstract 类(抽象构造函数)的类型签名.我知道它可以被定义为具有 Function 类型,但这方式太宽泛了.没有更精确的替代方法吗?

<小时>

为了澄清我的意思,以下小片段演示了抽象构造函数和非抽象构造函数之间的区别:

声明类型 ConstructorFunction = new (...args: any[]) =>任何;抽象类实用程序{...}var UtilityClass: ConstructorFunction = Utilities;//错误.

<块引用>

类型typeof Utilities"不可分配给类型new (...args: any[]) => any".

<块引用>

不能将抽象构造函数类型分配给非抽象构造函数类型.

解决方案

我自己也遇到了类似的问题,这似乎对我有用:

类型构造函数= 功能 &{原型:T}

The type signature for a non-abstract class (non-abstract constructor function) in TypeScript is the following:

declare type ConstructorFunction = new (...args: any[]) => any;

This is also called a newable type. However, I need a type signature for an abstract class (abstract constructor function). I understand it can be defined as having the type Function, but that is way too broad. Isn't there a more precise alternative?


Edit:

To clarify what I mean, the following little snippet demonstrates the difference between an abstract constructor and a non-abstract constructor:

declare type ConstructorFunction = new (...args: any[]) => any;

abstract class Utilities {
    ...
}

var UtilityClass: ConstructorFunction = Utilities; // Error.

Type 'typeof Utilities' is not assignable to type 'new (...args: any[]) => any'.

Cannot assign an abstract constructor type to a non-abstract constructor type.

解决方案

Was just struggling with a similar problem myself, and this seems to work for me:

type Constructor<T> = Function & { prototype: T }

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