序列化强类型对象的列表 [英] Serializing a list of strongly typed objects

问题描述

我可能已经在设计决策搞砸。相反，使用自定义对象的强类型集合中，我使用了一个泛型列表。从本质上讲，我拥有的是：

 公共类AreaFields
{
    [XmlArray（项目）]
    [XmlArrayItem（项目）]
    公开名单＆LT;＆领域GT; {字段设置;得到; }    [XmlAttribute]
    INT编号{设置;得到; }
}公共类字段
{
    [XmlAttribute]
    公共字符串名称{设置;得到; }
}
 

在整个应用程序，我已经使用列表＆LT; AreaFields＆GT; 现在，我需要序列化列表为XML。我所希望得到的是：

 ＆LT; SomeXMLTag＆GT;
    ＆LT; AreaFields ID ='1000'＆GT;
     ＆LT;项目＆GT;
       ＆LT;项目名称=测试1/＆GT;
       ＆LT;项目名称=Test2的/＆GT;
     ＆LT; /项目＆GT;
    ＆LT; / AreaFields＆GT;
    ＆LT; AreaFields ID ='1001'＆GT;
     ＆LT;项目＆GT;
       ＆LT;项目名称=测试1/＆GT;
       ＆LT;项目名称=Test2的/＆GT;
     ＆LT; /项目＆GT;
    ＆LT; / AreaFields＆GT;
    ＆LT; / SomeXMLTag＆GT;
 

既然不能序列化列表与LT;>（？还是可以的我），我将不得不序列化列表的每一个项目。

 例如：清单＆LT; AreaFields＆GT;名单=新名单，LT; AreaFields＆GT;（）;
//更多code以添加到列表
    列表[0] .GetRawXML（）; //一个方法，我必须序列
 

解决方案

您将需要一个包装类;那么序列 MyWrapper 的实例来获取XML按照您的例子。

  [XmlRoot（SomeXMLTag）]
公共类MyWrapper
{
    [XmlElement的（AreaFields）]
    公开名单＆LT; AreaFields＆GT; AreaFields {搞定;组; }
}公共类AreaFields
{
    [XmlArray（项目）]
    [XmlArrayItem（项目）]
    公开名单＆LT;＆领域GT; {字段设置;得到; }    [XmlAttribute]
    公众诠释ID {设置;得到; }
}公共类字段
{
    [XmlAttribute]
    公共字符串名称{设置;得到; }
}
 

I might have messed up on a design decision. Instead of using a strongly typed collection of custom objects, I have used a generic List. Essentially, what i have is:

public class AreaFields
{
    [XmlArray("Items")]
    [XmlArrayItem("Item")]
    public List<Fields> Fields { set; get; }

    [XmlAttribute]
    int id { set; get; }
}

public class Fields
{
    [XmlAttribute]
    public string Name { set; get; }
}

Throughout the application, I have used List<AreaFields> Now, I am in need of serializing the list into XML. What I am hoping to get is:

   <SomeXMLTag>
    <AreaFields id='1000'>
     <Items>
       <Item Name="Test1" />
       <Item Name="Test2" />
     </Items>
    </AreaFields>
    <AreaFields id='1001'>
     <Items>
       <Item Name="Test1" />
       <Item Name="Test2" />
     </Items>
    </AreaFields>
    </SomeXMLTag>

Since I cannot serialize List<> (or can I?), I will have to serialize every item of the list.

Ex: List<AreaFields> list = new List<AreaFields>();
//    more code to add to list
    list[0].GetRawXML(); //A method i have to serialize

解决方案

You'll need a wrapper class; then serialize the instance of MyWrapper to get the xml as per your example.

[XmlRoot("SomeXMLTag")]
public class MyWrapper
{
    [XmlElement("AreaFields")]
    public List<AreaFields> AreaFields { get; set; }
}

public class AreaFields
{
    [XmlArray("Items")]
    [XmlArrayItem("Item")]
    public List<Fields> Fields { set; get; }

    [XmlAttribute]
    public int id { set; get; }
}

public class Fields
{
    [XmlAttribute]
    public string Name { set; get; }
}

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