将浮点数格式化为 n 个小数位 [英] Format Float to n decimal places

问题描述

我需要将浮点数格式化为n"个小数位.

I need to format a float to "n"decimal places.

正在尝试 BigDecimal，但返回值不正确...

was trying to BigDecimal, but the return value is not correct...

public static float Redondear(float pNumero, int pCantidadDecimales) {
    // the function is call with the values Redondear(625.3f, 2)
    BigDecimal value = new BigDecimal(pNumero);
    value = value.setScale(pCantidadDecimales, RoundingMode.HALF_EVEN); // here the value is correct (625.30)
    return value.floatValue(); // but here the values is 625.3
}

我需要返回一个带有我指定的小数位数的浮点值.

I need to return a float value with the number of decimal places that I specify.

我需要 Float 值返回而不是 Double

I need Float value return not Double

.

推荐答案

你也可以传递浮点值，并使用:

You may also pass the float value, and use:

String.format("%.2f", floatValue);

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