如何通过四舍五入在Java中将double转换为int? [英] How to cast a double to an int in Java by rounding it down?

问题描述

我需要在 Java 中将 double 转换为 int，但数值必须始终向下取整.即 99.99999999 -> 99

I need to cast a double to an int in Java, but the numerical value must always round down. i.e. 99.99999999 -> 99

推荐答案

转换为 int 隐式丢弃任何小数.无需调用 Math.floor()(假设为正数)

Casting to an int implicitly drops any decimal. No need to call Math.floor() (assuming positive numbers)

简单地使用 (int) 进行类型转换，例如:

Simply typecast with (int), e.g.:

System.out.println((int)(99.9999)); // Prints 99

话虽如此，它确实与 Math.floor 有不同的行为，后者向负无穷大 (@Chris Wong) 舍入

This being said, it does have a different behavior from Math.floor which rounds towards negative infinity (@Chris Wong)

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