返回重叠的正则表达式 [英] Returning overlapping regular expressions

问题描述

是否有一个正则表达式可以捕获一个表达式的所有实例，而不管它们是否重叠?

Is there a regular expression that will capture all instances of an expression, regardless of whether or not they overlap?

例如在 /abc/def/ghi 中，如果我想捕获所有以 / 开头的字符串.正则表达式 (/.*) 只返回整个字符串，但我希望它匹配 /def/ghi 和 /ghi

E.g. in /abc/def/ghi if I want to capture all strings beginning with /. The regex (/.*) only returns the entire string, but I'd want it to match on /def/ghi and /ghi as well.

推荐答案

当然，匹配一个空字符串并在它后面放置一个前瞻，在捕获组中捕获 /.* :

Sure, match an empty string and place a look-ahead after it that captures /.* in a capturing group:

Matcher m = Pattern.compile("(?=(/.*))").matcher("/abc/def/ghi");
while(m.find()) {
  System.out.println(m.group(1));
}

会打印:

/abc/def/ghi
/def/ghi
/ghi

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