如何使用python读取7z文件的内容 [英] How to read contents of 7z file using python

问题描述

如何读取和保存 7z 的内容.我使用Python 2.7.9，我可以像这样提取或存档，但我无法在python中读取内容，我只在CMD中列出文件的内容

How can I read and save the contents of 7z. I use Python 2.7.9, I can extract or Archive like this, but I can't read contents in python, I only listing the file's contents in CMD

import subprocess
import os

source = 'filename.7z'
directory = 'C:Directory'
pw = '123456'
subprocess.call(r'"C:Program Files (x86)7-Zip7z.exe" x '+source +' -o'+directory+' -p'+pw)

推荐答案

如果你可以使用 python 3，有一个有用的库，py7zr，支持7zip存档压缩、解压、加解密.

If you can use python 3, there is a useful library, py7zr, which supports 7zip archive compression, decompression, encryption and decryption.

import py7zr
with py7zr.SevenZipFile('sample.7z', mode='r') as z:
    z.extractall()

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