Windows 中的 signal.alarm 替换 [Python] [英] signal.alarm replacement in Windows [Python]

问题描述

我有一个函数偶尔会挂起.

I have a function that occasionally hangs.

通常我会设置闹钟，但我使用的是 Windows 并且它不可用.

Normally I would set an alarm, but I'm in Windows and it's unavailable.

有没有简单的方法可以解决这个问题，还是我应该创建一个调用 time.sleep() 的线程?

Is there a simple way around this, or should I just create a thread that calls time.sleep()?

推荐答案

以下是原发帖者如何解决自己的问题:

Here's how the original poster solved his own problem:

结束了一个线程.唯一的技巧是使用 os._exit 而不是 sys.exit

Ended up going with a thread. Only trick was using os._exit instead of sys.exit

import os
import time
import threading

class Alarm (threading.Thread):
    def __init__ (self, timeout):
        threading.Thread.__init__ (self)
        self.timeout = timeout
        self.setDaemon (True)
    def run (self):
        time.sleep (self.timeout)
        os._exit (1)

alarm = Alarm (4)
alarm.start ()
time.sleep (2)
del alarm
print 'yup'

alarm = Alarm (4)
alarm.start ()
time.sleep (8)
del alarm
print 'nope'  # we don't make it this far

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