如何将这种格式的日期 (Tue Jul 13 00:00:00 CEST 2010) 转换为 Java 日期(字符串来自 alfresco 属性) [英] How to convert a date in this format (Tue Jul 13 00:00:00 CEST 2010) to a Java Date (The string comes from an alfresco property)

问题描述

我正在管理一个来自 Alfresco Properties 的日期并且在指定的(2010 年 7 月 13 日星期二 00:00:00 CEST)中，我需要将它转换为 Java 日期......我环顾四周并找到了数百万个关于各种字符串到日期转换形式的帖子，还有 这个页面所以我尝试了这样的事情:

i'm managing a date that comes from an Alfresco Properties and is in the specified (Tue Jul 13 00:00:00 CEST 2010) and i need to convert it to a Java date...i've looked around and found millions of posts for various string to date conversion form and also this page and so i tried something like this:

private static final DateFormat alfrescoDateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
Date dataRispostaDate = alfrescoDateFormat.parse(dataRisposta);

但它抛出一个异常.(异常是 (SSollevata un'eccezione durante la gestione della data: java.text.ParseException: Unparseable date: "Tue Jul 13 00:00:00 CEST 2011").

But it throws an exception.(The exception is (SSollevata un'eccezione durante la gestione della data: java.text.ParseException: Unparseable date: "Tue Jul 13 00:00:00 CEST 2011").

我贴出完整的代码:

        try {
            QName currDocTypeQName = (QName) nodeService.getType(doc);
            log.error("QName:["+currDocTypeQName.toString()+"]");
            if (currDocTypeQName != null) {
                String codAtto = AlfrescoConstants.getCodAttoFromQName(currDocTypeQName.toString());
                log.error("codAtto:["+codAtto+"]");
                if (codAtto.equals(AlfrescoConstants.COD_IQT)){
                    List<ChildAssociationRef> risposteAssociate = nodeService.getChildAssocs(doc, AlfrescoConstants.QN_RISPOSTEASSOCIATE, RegexQNamePattern.MATCH_ALL);
                    for (ChildAssociationRef childAssocRef : risposteAssociate) {
                        // Vado a prendere il nodo
                        NodeRef risposta = childAssocRef.getChildRef();
                        String dataRisposta = (nodeService.getProperty(risposta, AlfrescoConstants.QN_DATA_RISPOSTA)).toString();
                        log.error("dataRisposta:["+dataRisposta+"]");
                        if (!dataRisposta.isEmpty()){
                            try {
                                Date dataDa = dmyFormat.parse(req.getParameter("dataDa"));
                                log.error("dataDa:["+dataDa.toString()+"]");
                                Date dataA = dmyFormat.parse(req.getParameter("dataA"));
                                log.error("dataA:["+dataA.toString()+"]");
                                Date dataRispostaDate = alfrescoDateFormat.parse(dataRisposta);
                                log.error("dataRispostaDate:["+dataRispostaDate.toString()+"]");

                                if (dataRispostaDate.after(dataDa) && dataRispostaDate.before(dataA)){
                                    results.add(doc);
                                    log.error("La data risposta  è compresa tra le date specificate");
                                }else{
                                    log.error("La data risposta non è compresa tra le date specificate");
                                }
                            } catch (ParseException e) {
                                log.error("Sollevata un'eccezione durante la gestione della data: " + e);
                                throw new RuntimeException("Formato data non valido");
                            }
                        }else{
                            log.error("La data risposta non è specificata");
                        }
                    }
                }else{
                    results.add(doc);
                }
            }
        } catch (Exception e) {
            log.error("Sollevata un'eccezione durante la gestione del codice atto nel webscript nicola: " + e);
        }

有人可以帮忙吗?

推荐答案

基本上您的问题是您正在使用 SimpleDateFormat(String pattern) 构造函数，其中 javadoc 说:

Basically your problem is that you are using a SimpleDateFormat(String pattern) constructor, where javadoc says:

构造一个 SimpleDateFormat 使用给定的模式和默认日期默认语言环境的格式符号.

Constructs a SimpleDateFormat using the given pattern and the default date format symbols for the default locale.

如果您尝试使用此代码:

And if you try using this code:

DateFormat osLocalizedDateFormat = new SimpleDateFormat("MMMM EEEE");
System.out.println(osLocalizedDateFormat.format(new Date()))

您会注意到它会根据您的区域设置为您打印月份和星期几的标题.

you will notice that it prints you month and day of the week titles based on your locale.

问题的解决方案是使用 SimpleDateFormat(String pattern, Locale locale) 构造函数:

DateFormat dateFormat = new SimpleDateFormat(
            "EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
dateFormat.parse("Tue Jul 13 00:00:00 CEST 2011");
System.out.println(dateFormat.format(new Date()));

这篇关于如何将这种格式的日期 (Tue Jul 13 00:00:00 CEST 2010) 转换为 Java 日期(字符串来自 alfresco 属性)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！