方法接收器上的 golang 函数别名 [英] golang function alias on method receiver

问题描述

我可以为常用方法创建方法别名:

I can create method alias for an usual method:

func method1() {
    fmt.Println("method1")
}

var Method1 = method1

但不能对方法接收者做同样的事情:

But cannot do the same for a method receiver:

type Person struct {
    Name string
}

func (p *Person) methodReciver() {
    fmt.Println("method reciver")
}

var MethodReciver = methodReciver

在这种情况下，我在行 var MethodReciver = methodReciver 上得到了错误:

In this case I got the error on line var MethodReciver = methodReciver:

undefined: methodReciver

完整代码:

package main

import (
    "fmt"
)

type Person struct {
    Name string
}

func method1() {
    fmt.Println("method1")
}

var Method1 = method1

func (p *Person) methodReceiver() {
    fmt.Println("method receiver")
}

var MethodReceiver = methodReceiver

func main() {
    method1()
    Method1()
    p := Person{"Nick"}
    p.methodReceiver()
    p.MethodReceiver()
}

游乐场

是否可以为 methodReceiver 创建方法别名?

Is it possible to create a method alias for methodReceiver?

推荐答案

是的.您可以像这样创建别名:

Yes. You can make an alias like this:

var MethodReceiver = (*Person).methodReceiver

当你调用它时，你必须提供一个指向person对象的指针作为第一个参数:

When you call it, you have to provide a pointer to a person object as the first argument:

MethodReceiver(&p)

您可以在围棋操场上看到这一点.

这篇关于方法接收器上的 golang 函数别名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！