如何在 SQLite 数据库中存储图像 [英] How to store image in SQLite database
本文介绍了如何在 SQLite 数据库中存储图像的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
在我的应用程序中，我正在上传图库中的图像，我想将此图像存储在 SQLite 数据库中.如何在数据库中存储位图?我正在将位图转换为字符串并将其保存在数据库中.从数据库中检索它时，我无法将该字符串分配给 ImageView，因为它是一个字符串.
In my application I am uploading an image from gallery and I want to store this image in the SQLite database. How do I store a bitmap in the database? I am converting bitmap to a string and saving it in the database. While retrieving it from the database, I am not able to assign that string to ImageView since it is a string.
Imageupload12 .java:
Imageupload12 .java:
public class Imageupload12 extends Activity {
Button buttonLoadImage;
ImageView targetImage;
int i = 0;
Database database = new Database(this);
String i1;
String img;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main5);
buttonLoadImage = (Button) findViewById(R.id.loadimage);
targetImage = (ImageView) findViewById(R.id.targetimage);
Bundle b = getIntent().getExtras();
if (b != null) {
img = b.getString("image");
targetImage2.setImageURI("image");
//i am getting error as i cant assign string to imageview.
}
buttonLoadImage.setOnClickListener(new Button.OnClickListener() {
public void onClick(View arg0) {
// TODO Auto-generated method stub
Intent intent = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
Log.i("photo", "" + intent);
startActivityForResult(intent, i);
i = i + 1;
}
});
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case 0:
if (resultCode == RESULT_OK) {
Uri targetUri = data.getData();
// textTargetUri.setText(targetUri.toString());
Bitmap bitmap;
try {
bitmap = BitmapFactory.decodeStream(getContentResolver().openInputStream(targetUri));
targetImage.setImageBitmap(bitmap);
i1 = bitmap.toString();
Log.i("firstimage........", "" + i1);
targetImage.setVisibility(0);
SQLiteDatabase db = database.getWritableDatabase();
db.execSQL("INSERT INTO UPLOAD VALUES('" + i1 + "');");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
break;
}
}
}
图像.class:
public class Image extends Activity {
Database database = new Database(this);
static EfficientAdapter adapter, adapter1;
static ListView lv1;
static SQLiteDatabase db;
static EfficientAdapter adp;
static Cursor c1;
static Vector < String > IMAGE = new Vector < String > ();
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
db = database.getReadableDatabase();
c1 = db.rawQuery("select * from UPLOAD;", null);
if (c1.moveToFirst()) {
do {
IMAGE.add(c1.getString(0).toString());
} while (c1.moveToNext());
c1.close();
}
lv1 = (ListView) findViewById(R.id.List);
adapter = new EfficientAdapter(this);
lv1.setAdapter(adapter);
ImageView add = (ImageView) findViewById(R.id.imv1a);
add.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
IMAGE.clear();
Intent i = new Intent(Image.this, Imageupload12.class);
startActivity(i);
}
});
}
private static class EfficientAdapter extends BaseAdapter {
// protected final Context Context = null;
protected LayoutInflater mLayoutInflater;
AlertDialog.Builder aBuilder;
public EfficientAdapter(Context context) {
// TODO Auto-generated constructor stub
mLayoutInflater = LayoutInflater.from(context);
}
@Override
public int getCount() {
// TODO Auto-generated method stub
return IMAGE.size();
}
@Override
public Object getItem(int position) {
// TODO Auto-generated method stub
return position;
}
@Override
public long getItemId(int position) {
// TODO Auto-generated method stub
return position;
}
@Override
public View getView(final int position, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
final ViewHolder mVHolder;
if (convertView == null) {
convertView = mLayoutInflater.inflate(R.layout.pjtlistdetails, parent, false);
mVHolder = new ViewHolder();
mVHolder.t1 = (TextView) convertView.findViewById(R.id.pjtdetails);
mVHolder.time = (TextView) convertView.findViewById(R.id.name);
mVHolder.imv = (ImageButton) convertView.findViewById(R.id.editic);
mVHolder.imvd = (ImageView) convertView.findViewById(R.id.delete);
mVHolder.imvf = (ImageView) convertView.findViewById(R.id.fwd);
mVHolder.imv.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String img = IMAGE.elementAt(position);
Log.i("image...", "" + img);
Context ctx = v.getContext();
Intent myIntent = new Intent();
ctx = v.getContext();
myIntent.setClass(ctx, Imageupload12.class);
myIntent.putExtra("image", img);
ctx.startActivity(myIntent);
IMAGE.clear();
}
});
static class ViewHolder {
ImageButton imv;
ImageView imvd, imvf;
}
}
}
}
}
推荐答案
你必须使用blob"来存储图像.
You have to use "blob" to store image.
例如:将图像存储到数据库中:
ex: to store a image in to db:
public void insertImg(int id , Bitmap img ) {
byte[] data = getBitmapAsByteArray(img); // this is a function
insertStatement_logo.bindLong(1, id);
insertStatement_logo.bindBlob(2, data);
insertStatement_logo.executeInsert();
insertStatement_logo.clearBindings() ;
}
public static byte[] getBitmapAsByteArray(Bitmap bitmap) {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
bitmap.compress(CompressFormat.PNG, 0, outputStream);
return outputStream.toByteArray();
}
从数据库中检索图像:
public Bitmap getImage(int i){
String qu = "select img from table where feedid=" + i ;
Cursor cur = db.rawQuery(qu, null);
if (cur.moveToFirst()){
byte[] imgByte = cur.getBlob(0);
cur.close();
return BitmapFactory.decodeByteArray(imgByte, 0, imgByte.length);
}
if (cur != null && !cur.isClosed()) {
cur.close();
}
return null;
}
这篇关于如何在 SQLite 数据库中存储图像的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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