更改 ListView 上所选项目的背景颜色 [英] Change background color of selected item on a ListView

问题描述

我想知道如何更改 listView 上所选项目的背景颜色.我只想更改用户单击的特定项目，这意味着如果用户单击另一个项目，它将是突出显示的项目.好吧，因为我希望它尽可能保持简单并使用默认的 android 列表视图，所以我改用了以下代码:

I want to know on how I can change the background color of the selected item on my listView. I only want to change the specific item clicked by the user, meaning if the user clicks another item it will be the one which is highlighted. Well since I want it to keep simple as possible and use the default android listview I used this code instead:

record_list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
                try{
                    for (int ctr=0;ctr<=record_items.length;ctr++){
                        if(i==ctr){
                            record_list.getChildAt(ctr).setBackgroundColor(Color.CYAN);
                        }else{
                            record_list.getChildAt(ctr).setBackgroundColor(Color.WHITE);
                        }
                    }
                }
                catch (Exception e){
                    e.printStackTrace();
                }
                Log.v("Selected item",record_list.getItemAtPosition(i));
            }
        });

好的，这个工作正常，但问题是它很慢.现在我想知道是否还有其他方法可以提供与我所做的相同的输出.

Ok this one is working but the problem is that it's slow. Now I want to know if there's any other way around that I can do which will give the same output as I made.

我尝试使用 record_list.getSelectedView().setBackgroundColor(Color.CYAN); 但它给了我一个空指针异常.

I tried using record_list.getSelectedView().setBackgroundColor(Color.CYAN); but it gives me a null pointer exception.

我也尝试过 selector.xml 但它也没有成功.此外，ListView 上有一个属性，称为 listSelector.正如文档Drawable 用于指示列表中当前选定的项目"所述，它是一个可绘制对象.我也相信这应该可以解决问题，是的，它可以在我的模拟器上完成，但不能在我的 Galaxy 选项卡上完成.我也尝试了其他方法，但没有任何效果如我所愿.

I also tried the selector.xml but it also didn't do the trick. Furthermore, there is one properties here on ListView which is called listSelector. It's a drawable as said by the documentation "Drawable used to indicate the currently selected item in the list." I also believe that this should do the trick and yes it do the trick on my emulator but not on my galaxy tab. I also tried the other methods but nothing works as I wanted it to be.

推荐答案

可以跟踪当前选中元素的位置:

You can keep track the position of the current selected element:

    OnItemClickListener listViewOnItemClick = new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> adapter, View arg1, int position, long id) {
                mSelectedItem = position;
                mAdapter.notifyDataSetChanged();
        }
    };

并覆盖适配器的 getView 方法:

And override the getView method of your adapter:

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        final View view = View.inflate(context, R.layout.item_list, null);

        if (position == mSelectedItem) {
            // set your color
        }

        return view;
    }

对我来说它成功了.

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