从 Android 中的 ViewPager 中删除 Fragment Page [英] Remove Fragment Page from ViewPager in Android

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本文介绍了从 Android 中的 ViewPager 中删除 Fragment Page的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试从 ViewPager 中动态添加和删除 Fragments,添加工作没有任何问题,但删除无法按预期工作.

I'm trying to dynamically add and remove Fragments from a ViewPager, adding works without any problems, but removing doesn't work as expected.

每次我想删除当前项目时,最后一个都会被删除.

Everytime I want to remove the current item, the last one gets removed.

我还尝试在适配器的 getItemPosition 方法中使用 FragmentStatePagerAdapter 或返回 POSITION_NONE.

I also tried to use an FragmentStatePagerAdapter or return POSITION_NONE in the adapter's getItemPosition method.

我做错了什么?

这是一个基本示例:

MainActivity.java

public class MainActivity extends FragmentActivity implements TextProvider {

    private Button mAdd;
    private Button mRemove;
    private ViewPager mPager;

    private MyPagerAdapter mAdapter;

    private ArrayList<String> mEntries = new ArrayList<String>();

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        mEntries.add("pos 1");
        mEntries.add("pos 2");
        mEntries.add("pos 3");
        mEntries.add("pos 4");
        mEntries.add("pos 5");

        mAdd = (Button) findViewById(R.id.add);
        mRemove = (Button) findViewById(R.id.remove);
        mPager = (ViewPager) findViewById(R.id.pager);

        mAdd.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View view) {
                addNewItem();
            }
        });

        mRemove.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View view) {
                removeCurrentItem();
            }
        });

        mAdapter = new MyPagerAdapter(this.getSupportFragmentManager(), this);

        mPager.setAdapter(mAdapter);

    }

    private void addNewItem() {
        mEntries.add("new item");
        mAdapter.notifyDataSetChanged();
    }

    private void removeCurrentItem() {
        int position = mPager.getCurrentItem();
        mEntries.remove(position);
        mAdapter.notifyDataSetChanged();
    }

    @Override
    public String getTextForPosition(int position) {
        return mEntries.get(position);
    }
    @Override
    public int getCount() {
        return mEntries.size();
    }


    private class MyPagerAdapter extends FragmentPagerAdapter {

        private TextProvider mProvider;

        public MyPagerAdapter(FragmentManager fm, TextProvider provider) {
            super(fm);
            this.mProvider = provider;
        }

        @Override
        public Fragment getItem(int position) {
            return MyFragment.newInstance(mProvider.getTextForPosition(position));
        }

        @Override
        public int getCount() {
            return mProvider.getCount();
        }

    }

}

TextProvider.java

public interface TextProvider {
    public String getTextForPosition(int position);
    public int getCount();
}

MyFragment.java

public class MyFragment extends Fragment {

    private String mText;

    public static MyFragment newInstance(String text) {
        MyFragment f = new MyFragment(text);
        return f;
    }

    public MyFragment() {
    }

    public MyFragment(String text) {
        this.mText = text;
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {

        View root = inflater.inflate(R.layout.fragment, container, false);

        ((TextView) root.findViewById(R.id.position)).setText(mText);

        return root;
    }

}

activity_main.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <Button
        android:id="@+id/add"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="add new item" />

    <Button
        android:id="@+id/remove"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="remove current item" />

    <android.support.v4.view.ViewPager
        android:id="@+id/pager"
        android:layout_width="match_parent"
        android:layout_height="0dip"
        android:layout_weight="1" />

</LinearLayout>

fragment.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/position"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:gravity="center"
        android:textSize="35sp" />

</LinearLayout>

推荐答案

Louth 的解决方案不足以让我工作,因为现有的片段没有被破坏.受 this answer 的启发,我发现解决方案是覆盖 getItemId(int position)FragmentPagerAdapter 方法在 Fragment 的预期位置发生变化时给出一个新的唯一 ID.

The solution by Louth was not enough to get things working for me, as the existing fragments were not getting destroyed. Motivated by this answer, I found that the solution is to override the getItemId(int position) method of FragmentPagerAdapter to give a new unique ID whenever there has been a change in the expected position of a Fragment.

private class MyPagerAdapter extends FragmentPagerAdapter {

    private TextProvider mProvider;
    private long baseId = 0;

    public MyPagerAdapter(FragmentManager fm, TextProvider provider) {
        super(fm);
        this.mProvider = provider;
    }

    @Override
    public Fragment getItem(int position) {
        return MyFragment.newInstance(mProvider.getTextForPosition(position));
    }

    @Override
    public int getCount() {
        return mProvider.getCount();
    }


    //this is called when notifyDataSetChanged() is called
    @Override
    public int getItemPosition(Object object) {
        // refresh all fragments when data set changed
        return PagerAdapter.POSITION_NONE;
    }


    @Override
    public long getItemId(int position) {
        // give an ID different from position when position has been changed
        return baseId + position;
    }

    /**
     * Notify that the position of a fragment has been changed.
     * Create a new ID for each position to force recreation of the fragment
     * @param n number of items which have been changed
     */
    public void notifyChangeInPosition(int n) {
        // shift the ID returned by getItemId outside the range of all previous fragments
        baseId += getCount() + n;
    }
}

现在,例如,如果您删除单个选项卡或对订单进行一些更改,您应该在调用 notifyDataSetChanged() 之前调用 notifyChangeInPosition(1),这将确保将重新创建所有 Fragment.

Now, for example if you delete a single tab or make some change to the order, you should call notifyChangeInPosition(1) before calling notifyDataSetChanged(), which will ensure that all the Fragments will be recreated.

覆盖 getItemPosition():

notifyDataSetChanged()被调用时,适配器调用它所附加的ViewPagernotifyChanged()方法.ViewPager 然后检查适配器的 getItemPosition() 为每个项目返回的值,删除那些返回 POSITION_NONE 的项目(请参阅 源代码) 然后重新填充.

When notifyDataSetChanged() is called, the adapter calls the notifyChanged() method of the ViewPager which it is attached to. The ViewPager then checks the value returned by the adapter's getItemPosition() for each item, removing those items which return POSITION_NONE (see the source code) and then repopulating.

覆盖 getItemId():

这对于防止适配器在重新填充 ViewPager 时重新加载旧片段是必要的.您可以通过查看 FragmentPagerAdapter 中instantiateItem() 的源代码.

This is necessary to prevent the adapter from reloading the old fragment when the ViewPager is repopulating. You can easily understand why this works by looking at the source code for instantiateItem() in FragmentPagerAdapter.

    final long itemId = getItemId(position);

    // Do we already have this fragment?
    String name = makeFragmentName(container.getId(), itemId);
    Fragment fragment = mFragmentManager.findFragmentByTag(name);
    if (fragment != null) {
        if (DEBUG) Log.v(TAG, "Attaching item #" + itemId + ": f=" + fragment);
        mCurTransaction.attach(fragment);
    } else {
        fragment = getItem(position);
        if (DEBUG) Log.v(TAG, "Adding item #" + itemId + ": f=" + fragment);
        mCurTransaction.add(container.getId(), fragment,
                makeFragmentName(container.getId(), itemId));
    }

如您所见,getItem() 方法仅在片段管理器未找到具有相同 Id 的现有片段时才被调用.对我来说,即使在调用 notifyDataSetChanged() 之后,旧片段仍然附加在我看来似乎是一个错误,但 ViewPager 的文档明确指出:

As you can see, the getItem() method is only called if the fragment manager finds no existing fragments with the same Id. To me it seems like a bug that the old fragments are still attached even after notifyDataSetChanged() is called, but the documentation for ViewPager does clearly state that:

请注意,该类目前处于早期设计和开发阶段.API 可能会在兼容性库的后续更新中发生变化,需要在针对较新版本编译应用时更改应用的源代码.

Note this class is currently under early design and development. The API will likely change in later updates of the compatibility library, requiring changes to the source code of apps when they are compiled against the newer version.

因此希望在未来版本的支持库中不需要这里给出的解决方法.

So hopefully the workaround given here will not be necessary in a future version of the support library.

这篇关于从 Android 中的 ViewPager 中删除 Fragment Page的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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