如何从 URL 字符串中获取参数? [英] How can I get parameters from a URL string?

问题描述

我有一个 HTML 表单字段 $_POST["url"]，有一些 URL 字符串作为值.

示例值为:

<前>https://example.com/test/1234?email=[e-mail]://example.com/test/1234?basic=2&email=[e-mail]://example.com/test/1234?email=[e-mail]://example.com/test/1234?email=[e-mail]&testin=123https://example.com/test/the-page-here/1234?someurl=key&email=[e-mail]

等

如何才能从这些 URL/值中只获取 email 参数?

请注意，我不是从浏览器地址栏中获取这些字符串的.

解决方案

您可以使用 parse_url() 和 parse_str() 为此.

$parts = parse_url($url);parse_str($parts['query'], $query);回声 $query['email'];

如果你想用PHP动态获取$url，看看这个问题:

获取 PHP 中的完整 URL

I have an HTML form field $_POST["url"], having some URL strings as the value.

Example values are:

https://example.com/test/1234?email=[e-mail]
https://example.com/test/1234?basic=2&email=[e-mail]
https://example.com/test/1234?email=[e-mail]
https://example.com/test/1234?email=[e-mail]&testin=123
https://example.com/test/the-page-here/1234?someurl=key&email=[e-mail]

etc.

How can I get only the email parameter from these URLs/values?

Please note that I am not getting these strings from the browser address bar.

解决方案

You can use the parse_url() and parse_str() for that.

$parts = parse_url($url);
parse_str($parts['query'], $query);
echo $query['email'];

If you want to get the $url dynamically with PHP, take a look at this question:

Get the full URL in PHP

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