如何在 PHP 中比较两个日期? [英] How can I compare two dates in PHP?

问题描述

如何在 PHP 中比较两个日期?

How can I compare two dates in PHP?

日期以如下格式存储在数据库中

The date is stored in the database in the following format

2011-10-2

如果我想将今天的日期与数据库中的日期进行比较，看看哪个更大，我该怎么做?

If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?

我试过了，

$today = date("Y-m-d");
$expire = $row->expireDate //from db

if($today < $expireDate) { //do something; }

但它并不是真的那样工作.还有什么方法可以做到?

but it doesn't really work that way. What's another way of doing it?

推荐答案

在数据库中日期看起来像这样 2011-10-2

in the database the date looks like this 2011-10-2

将其存储在 YYYY-MM-DD 中，然后字符串比较将起作用，因为 '1' > '0' 等

Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.

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