将数据框字符串列拆分为多列 [英] Split data frame string column into multiple columns

问题描述

我想获取表单的数据

before = data.frame(attr = c(1,30,4,6), type=c('foo_and_bar','foo_and_bar_2'))
  attr          type
1    1   foo_and_bar
2   30 foo_and_bar_2
3    4   foo_and_bar
4    6 foo_and_bar_2

并在上面的type"列上使用 split() 以获得如下内容:

and use split() on the column "type" from above to get something like this:

  attr type_1 type_2
1    1    foo    bar
2   30    foo  bar_2
3    4    foo    bar
4    6    foo  bar_2

我想出了令人难以置信的复杂方法，涉及某种形式的 apply 有效，但后来我把它放错了地方.这似乎太复杂了，不是最好的方法.我可以使用 strsplit 如下，但不清楚如何将其恢复为数据框中的 2 列.

I came up with something unbelievably complex involving some form of apply that worked, but I've since misplaced that. It seemed far too complicated to be the best way. I can use strsplit as below, but then unclear how to get that back into 2 columns in the data frame.

> strsplit(as.character(before$type),'_and_')
[[1]]
[1] "foo" "bar"

[[2]]
[1] "foo"   "bar_2"

[[3]]
[1] "foo" "bar"

[[4]]
[1] "foo"   "bar_2"

感谢您的指点.我还没有完全了解 R 列表.

Thanks for any pointers. I've not quite groked R lists just yet.

推荐答案

使用 stringr::str_split_fixed

library(stringr)
str_split_fixed(before$type, "_and_", 2)

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