除以 1/n 总是返回 0.0 [英] Dividing 1/n always returns 0.0

问题描述

我正在尝试计算 p1=(1/1)*(1/2)*...*(1/n) 但出了点问题，printf 给我 0.000...0

I am trying to calculate p1=(1/1)*(1/2)*...*(1/n) but something is wrong and the printf gives me 0.000...0

#include <stdio.h>

int main(void) {

    int i,num;
    float p3;

    do {
        printf ("give number N>3 : 
" );
        scanf( "%d", &num );
    } while( num <= 3 );

    i = 1;
    p3 = 1;  

    do {
        p3=p3*(1/i);
        printf( "%f
",p3 );
    } while ( i <= num );

    printf("
P3=%f",p3);
    return 0;
}

推荐答案

(1/i)

i 是一个 int，所以是整数除法，如果 i >1.使用 1.0/i 进行浮点除法.

i is an int, so that's integer division, resulting in 0 if i > 1. Use 1.0/i to get floating point division.

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