如何将 JSON 对象转换为 TypeScript 类? [英] How do I cast a JSON Object to a TypeScript class?
问题描述
我从远程 REST 服务器读取了一个 JSON 对象.这个 JSON 对象具有 typescript 类的所有属性(按设计).如何将接收到的 JSON 对象转换为类型 var?
I read a JSON object from a remote REST server. This JSON object has all the properties of a typescript class (by design). How do I cast that received JSON object to a type var?
我不想填充 typescript var(即有一个接受这个 JSON 对象的构造函数).它很大并且通过子对象复制子对象中的所有内容&逐个属性会花费很多时间.
I don't want to populate a typescript var (ie have a constructor that takes this JSON object). It's large and copying everything across sub-object by sub-object & property by property would take a lot of time.
更新:你可以将其转换为打字稿界面！
推荐答案
您不能简单地将来自 Ajax 请求的普通 JavaScript 结果转换为原型 JavaScript/TypeScript 类实例.有许多技术可以做到这一点，通常涉及复制数据.除非您创建类的实例，否则它不会有任何方法或属性.它将仍然是一个简单的 JavaScript 对象.
You can't simple cast a plain-old-JavaScript result from an Ajax request into a prototypical JavaScript/TypeScript class instance. There are a number of techniques for doing it, and generally involve copying data. Unless you create an instance of the class, it won't have any methods or properties. It will remain a simple JavaScript object.
虽然如果你只处理数据，你可以只对接口进行强制转换(因为它纯粹是一个编译时结构)，这需要你使用一个使用数据实例并执行操作的 TypeScript 类数据.
While if you only were dealing with data, you could just do a cast to an interface (as it's purely a compile time structure), this would require that you use a TypeScript class which uses the data instance and performs operations with that data.
复制数据的一些例子:
本质上，您只需:
var d = new MyRichObject();
d.copyInto(jsonResult);
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