如何从 Json 序列化中排除属性 [英] How to exclude property from Json Serialization

问题描述

我有一个序列化的 DTO 类

I have a DTO class which I Serialize

Json.Serialize(MyClass)

如何排除它的公共属性?

(它必须是公开的，因为我在其他地方的代码中使用它)

(It has to be public, as I use it in my code somewhere else)

推荐答案

如果您使用的是 Json.Net 属性 [JsonIgnore] 将简单地忽略字段/属性，而序列化或反序列化.

If you are using Json.Net attribute [JsonIgnore] will simply ignore the field/property while serializing or deserialising.

public class Car
{
  // included in JSON
  public string Model { get; set; }
  public DateTime Year { get; set; }
  public List<string> Features { get; set; }

  // ignored
  [JsonIgnore]
  public DateTime LastModified { get; set; }
}

或者您可以使用 DataContract 和 DataMember 属性来选择性地序列化/反序列化属性/字段.

Or you can use DataContract and DataMember attribute to selectively serialize/deserialize properties/fields.

[DataContract]
public class Computer
{
  // included in JSON
  [DataMember]
  public string Name { get; set; }
  [DataMember]
  public decimal SalePrice { get; set; }

  // ignored
  public string Manufacture { get; set; }
  public int StockCount { get; set; }
  public decimal WholeSalePrice { get; set; }
  public DateTime NextShipmentDate { get; set; }
}

参考 http://james.newtonking.com/archive/2009/10/23/efficient-json-with-json-net-reducing-serialized-json-size 了解更多详情

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