Django 可选的 url 参数 [英] Django optional url parameters

问题描述

我有一个像这样的 Django URL:

I have a Django URL like this:

url(
    r'^project_config/(?P<product>w+)/(?P<project_id>w+)/$',
    'tool.views.ProjectConfig',
    name='project_config'
),

views.py:

def ProjectConfig(request, product, project_id=None, template_name='project.html'):
    ...
    # do stuff

问题是我希望 project_id 参数是可选的.

The problem is that I want the project_id parameter to be optional.

我希望 /project_config/ 和 /project_config/12345abdce/ 是同样有效的 URL 模式，以便 if project_id 已通过，然后我可以使用它.

I want /project_config/ and /project_config/12345abdce/ to be equally valid URL patterns, so that if project_id is passed, then I can use it.

就目前而言，当我访问没有 project_id 参数的 URL 时，我得到 404.

As it stands at the moment, I get a 404 when I access the URL without the project_id parameter.

推荐答案

有几种方法.

一种是在正则表达式中使用非捕获组:(?:/(?P