如何在 Django 模板中的字典中迭代字典? [英] how to iterate through dictionary in a dictionary in django template?

问题描述

我的字典看起来像这样(字典中的字典):

My dictionary looks like this(Dictionary within a dictionary):

{'0': {
    'chosen_unit': <Unit: Kg>,
    'cost': Decimal('10.0000'),
    'unit__name_abbrev': u'G',
    'supplier__supplier': u"Steve's Meat Locker",
    'price': Decimal('5.00'),
    'supplier__address': u'No
address here',
    'chosen_unit_amount': u'2',
    'city__name': u'Joburg, Central',
    'supplier__phone_number': u'02299944444',
    'supplier__website': None,
    'supplier__price_list': u'',
    'supplier__email': u'[e-mail]',
    'unit__name': u'Gram',
    'name': u'Rump Bone',
}}

现在我只是想在我的模板上显示信息，但我很挣扎.我的模板代码如下所示:

Now I'm just trying to display the information on my template but I'm struggling. My code for the template looks like:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {{ ingredient }}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

它只是在我的模板上显示0"?

It just shows me '0' on my template?

我也试过:

{% for ingredient in landing_dict.ingredients %}
  {{ ingredient.cost }}
{% endfor %}

这甚至不显示结果.

我想也许我需要更深一层地迭代，所以尝试了这个:

I thought perhaps I need to iterate one level deeper so tried this:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {% for field in ingredient %}
      {{ field }}
    {% endfor %}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

但这并没有显示任何内容.

But this doesn't display anything.

我做错了什么?

推荐答案

假设你的数据是 -

data = {'a': [ [1, 2] ], 'b': [ [3, 4] ],'c':[ [5,6]] }

您可以使用 data.items() 方法来获取字典元素.请注意，在 django 模板中，我们不放置 ().还有一些用户提到 values[0] 不起作用，如果是这种情况，请尝试 values.items.

You can use the data.items() method to get the dictionary elements. Note, in django templates we do NOT put (). Also some users mentioned values[0] does not work, if that is the case then try values.items.

<table>
    <tr>
        <td>a</td>
        <td>b</td>
        <td>c</td>
    </tr>

    {% for key, values in data.items %}
    <tr>
        <td>{{key}}</td>
        {% for v in values[0] %}
        <td>{{v}}</td>
        {% endfor %}
    </tr>
    {% endfor %}
</table>

我很确定您可以将此逻辑扩展到您的特定字典.

Am pretty sure you can extend this logic to your specific dict.

按排序顺序迭代字典键 - 首先我们在 python 中排序，然后迭代 &在 Django 模板中渲染.

To iterate over dict keys in a sorted order - First we sort in python then iterate & render in django template.

return render_to_response('some_page.html', {'data': sorted(data.items())})

在模板文件中:

{% for key, value in data %}
    <tr>
        <td> Key: {{ key }} </td> 
        <td> Value: {{ value }} </td>
    </tr>
{% endfor %}

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