使用 RegExp 删除所有特殊字符 [英] Remove all special characters with RegExp
问题描述
我想要一个可以从字符串中删除所有特殊字符的 RegExp.我正在尝试类似的东西,但它在 IE7 中不起作用,尽管它在 Firefox 中有效.
I would like a RegExp that will remove all special characters from a string. I am trying something like this but it doesn’t work in IE7, though it works in Firefox.
var specialChars = "!@#$^&%*()+=-[]/{}|:<>?,.";
for (var i = 0; i < specialChars.length; i++) {
stringToReplace = stringToReplace.replace(new RegExp("\" + specialChars[i], "gi"), "");
}
对 RegExp 的详细描述也会有所帮助.
A detailed description of the RegExp would be helpful as well.
推荐答案
var desired = stringToReplace.replace(/[^ws]/gi, '')
正如评论中提到的,将其作为白名单更容易 - 替换不在您的安全列表中的字符.
As was mentioned in the comments it's easier to do this as a whitelist - replace the characters which aren't in your safelist.
插入符号(^
)是集合[...]
的否定,gi
表示全局且不区分大小写(后者有点多余,但我想提一下)并且这个例子中的安全列表是数字、单词字符、下划线(w
)和空格(s
).
The caret (^
) character is the negation of the set [...]
, gi
say global and case-insensitive (the latter is a bit redundant but I wanted to mention it) and the safelist in this example is digits, word characters, underscores (w
) and whitespace (s
).
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