对于不规则的分隔符,如何使 Pandas read_csv 中的分隔符更灵活,wrt 空格? [英] How to make separator in pandas read_csv more flexible wrt whitespace, for irregular separators?
问题描述
我需要使用 read_csv
方法通过从文件中读取数据来创建数据框.然而,分隔符不是很规则:一些列用制表符 (
) 分隔,其他的用空格分隔.此外,某些列可以由 2 个或 3 个或更多空格分隔,甚至可以由空格和制表符的组合分隔(例如 3 个空格、两个制表符然后是 1 个空格).
有没有办法告诉pandas正确处理这些文件?
顺便说一句,如果我使用Python,我就没有这个问题.我用:
用于文件中的行(file_name):fld = line.split()
它完美无缺.它不关心字段之间是否有 2 或 3 个空格.即使是空格和制表符的组合也不会造成任何问题.大熊猫也可以吗?
来自 文档,您可以使用正则表达式或 delim_whitespace
:
I need to create a data frame by reading in data from a file, using read_csv
method. However, the separators are not very regular: some columns are separated by tabs (
), other are separated by spaces. Moreover, some columns can be separated by 2 or 3 or more spaces or even by a combination of spaces and tabs (for example 3 spaces, two tabs and then 1 space).
Is there a way to tell pandas to treat these files properly?
By the way, I do not have this problem if I use Python. I use:
for line in file(file_name):
fld = line.split()
And it works perfect. It does not care if there are 2 or 3 spaces between the fields. Even combinations of spaces and tabs do not cause any problem. Can pandas do the same?
From the documentation, you can use either a regex or delim_whitespace
:
>>> import pandas as pd
>>> for line in open("whitespace.csv"):
... print repr(line)
...
'a b c 1 2
'
'd e f 3 4
'
>>> pd.read_csv("whitespace.csv", header=None, delimiter=r"s+")
0 1 2 3 4
0 a b c 1 2
1 d e f 3 4
>>> pd.read_csv("whitespace.csv", header=None, delim_whitespace=True)
0 1 2 3 4
0 a b c 1 2
1 d e f 3 4
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