如何在合并 pandas 数据框中的两列时删除 nan 值? [英] How to remove nan value while combining two column in Panda Data frame?

问题描述

我正在尝试但无法在组合 DataFrame 的两列时删除 nan.

I am trying but not able to remove nan while combining two columns of a DataFrame.

数据就像:

feedback_id                  _id
568a8c25cac4991645c287ac     nan    
568df45b177e30c6487d3603     nan    
nan                          568df434832b090048f34974       
nan                          568cd22e9e82dfc166d7dff1   
568df3f0832b090048f34711     nan
nan                          568e5a38b4a797c664143dda   

我想要:

feedback_request_id
568a8c25cac4991645c287ac
568df45b177e30c6487d3603
568df434832b090048f34974
568cd22e9e82dfc166d7dff1
568df3f0832b090048f34711
568e5a38b4a797c664143dda

这是我的代码:

df3['feedback_request_id'] = ('' if df3['_id'].empty else df3['_id'].map(str)) + ('' if df3['feedback_id'].empty else df3['feedback_id'].map(str))

我得到的输出:

feedback_request_id
568a8c25cac4991645c287acnan
568df45b177e30c6487d3603nan
nan568df434832b090048f34974
nan568cd22e9e82dfc166d7dff1
568df3f0832b090048f34711nan
nan568e5a38b4a797c664143dda

我也试过这个:

df3['feedback_request_id'] = ('' if df3['_id']=='nan' else df3['_id'].map(str)) + ('' if df3['feedback_id']=='nan' else df3['feedback_id'].map(str))

但它给出了错误:

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

推荐答案

您可以使用 combine_first 或 填充:

You can use combine_first or fillna:

print df['feedback_id'].combine_first(df['_id'])
0    568a8c25cac4991645c287ac
1    568df45b177e30c6487d3603
2    568df434832b090048f34974
3    568cd22e9e82dfc166d7dff1
4    568df3f0832b090048f34711
5    568e5a38b4a797c664143dda
Name: feedback_id, dtype: object

print df['feedback_id'].fillna(df['_id'])
0    568a8c25cac4991645c287ac
1    568df45b177e30c6487d3603
2    568df434832b090048f34974
3    568cd22e9e82dfc166d7dff1
4    568df3f0832b090048f34711
5    568e5a38b4a797c664143dda
Name: feedback_id, dtype: object

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