通过 ajax 将 Javascript 变量传递给 PHP [英] Pass Javascript variable to PHP via ajax

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本文介绍了通过 ajax 将 Javascript 变量传递给 PHP的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图将一个变量从我的 javascript 代码传递到服务器端 PHP 代码.我知道这必须通过 ajax 调用来完成,我相信我已经正确完成了,但是当我遇到麻烦时,因为我是 php 新手,访问我从我的 ajax 传递到我的 php 的变量.这是我迄今为止的代码:

I am trying to pass a variable from my javascript code over to the server side PHP code. I know this must be done via an ajax call which i believe i have done correctly, however accessing the variable i pass from my ajax into my php is when i run into trouble as i am new to php. Here is my code i have thus far:

$(document).ready(function() {

            $(".clickable").click(function() {
                var userID = $(this).attr('id');
                //alert($(this).attr('id'));
                $.ajax({
                    type: "POST",
                    url: 'logtime.php',
                    data: "userID=" + userID,
                    success: function(data)
                    {
                        alert("success!");
                    }
                });
            });
        });

<?php //logtime.php
$uid = isset($_POST['userID']);
//rest of code that uses $uid
?>

我正在尝试将我的 javascript 变量userID"传递给 php ($userID),但是我在路上的某个地方出错了.感谢您的帮助!

I'm trying to pass my javascript variable "userID" to php ($userID), however i've gone wrong somewhere along the road. Thanks for the help!

推荐答案

将这样的数据传给ajax调用(http://api.jquery.com/jQuery.ajax/):

Pass the data like this to the ajax call (http://api.jquery.com/jQuery.ajax/):

data: { userID : userID }

并在您的 PHP 中执行此操作:

And in your PHP do this:

if(isset($_POST['userID']))
{
    $uid = $_POST['userID'];

    // Do whatever you want with the $uid
}

isset() 函数的目的是检查给定的变量是否存在,而不是获取它的值.

isset() function's purpose is to check wheter the given variable exists, not to get its value.

这篇关于通过 ajax 将 Javascript 变量传递给 PHP的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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